1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
d1i1m1o1n [39]
4 years ago
15

A scientist carries out a reaction twice. In Trial A, the scientist combines the reactants in a container. In Trial B, the scien

tist combines the reactants in the same container, but she also adds a catalyst. If everything else is the same about the two trials, what is most likely true about Trial B?
Chemistry
2 answers:
nirvana33 [79]4 years ago
8 0

Answer:

It will have a lower activation energy than Trial A.

Explanation:

Trail B will have a lower activation energy than trail A because in this trial the scientist adds a catalyst. Catalysts slow down reaction rates which will in turn mean a lower activation.

Paha777 [63]4 years ago
7 0
It would be C because It will have a lower activation energy than Trial A.
You might be interested in
A 7.27-gram sample of a compound is dissolved in 250. grams of benzene. The freezing point of this solution is 1.02°C below that
UkoKoshka [18]

Answer:

The correct answer is 146 g/mol

Explanation:

<em>Freezing point depression</em> is a colligative property related to the number of particles of solute dissolved in a solvent. It is given by:

ΔTf = Kf x m

Where ΔTf is the freezing point depression (in ºC), Kf is a constant for the solvent and m is the molality of solution. From the problem, we know the following data:

ΔTf = 1.02ºC

Kf = 5.12ºC/m

From this, we can calculate the molality:

m = ΔTf/Kf = 1.02ºC/(5.12ºC/m)= 0.199 m

The molality of a solution is defined as the moles of solute per kg of solvent. Thus, we can multiply the molality by the mass of solvent in kg (250 g= 0.25 kg) to obtain the moles of solute:

0.199 mol/kg benzene x 0.25 kg = 0.0498 moles solute

There are 0.0498 moles of solute dissolved in the solution. To calculate the molar mass of the solute, we divide the mass (7.27 g) into the moles:

molar mass = mass/mol = 7.27 g/(0.0498 mol) = 145.9 g/mol ≅ 146 g/mol

<em>Therefore, the molar mass of the compound is 146 g/mol </em>

6 0
3 years ago
How many kJ are 3,340J?
forsale [732]
The answer I believe is 3.340kj.
8 0
3 years ago
What do we assume about the volume of the actual molecules themselves in a sample of gas, compared to the bulk volume of the gas
Firlakuza [10]

We assume that the volume of the molecules themselves in a gas sample is negligible compared to the bulk volume of the gas sample: this helps us to explain why gases are so compressible.

4 0
3 years ago
List of charge of elements that do not form compound easily​
adelina 88 [10]

Answer:

The highlighted words in the explanation.

Explanation:

A clue comes by considering the noble gas elements, the rightmost column of the periodic table. These elements—helium, neon, argon, krypton, xenon, and radon—do not form compounds very easily, which suggests that they are especially stable as lone atoms. What else do the noble gas elements have in common?

7 0
3 years ago
1. A student sees tiny bubbles clinging to the inside of an unopened plastic bottle full of carbonated soft drinks. The student
Lina20 [59]

Answer:

1) The bubbles will grow, and more may appear.

2)Can A will make a louder and stronger fizz than can B.

Explanation:

When you squeeze the sides of the bottle you increase the pressure pushing on the bubble, making it compress into a smaller space. This decrease in volume causes the bubble to increase in density. When the bubble increases in density, the bubble will grow and more bubbles will appear. Therefore, Changing the pressure (by squeezing the bottle) changes the volume of the bubbles. The number of bubbles doesn't change, just their size increases.

Carbonated drinks tend to lose their fizz at higher temperatures because the loss of carbon dioxide in liquids is increased as temperature is raised. This can be explained by the fact that when carbonated liquids are exposed to high temperatures, the solubility of gases in them is decreased. Hence the solubility of CO2 gas in can A at 32°C is less than the solubility of CO2 in can B at 8°C. Thus can A will tend to make a louder fizz more than can B.

3 0
3 years ago
Other questions:
  • Calculate the pressure of O2 (in atm) over a sample of NiO at 25.00°C if ΔG o = 212 kJ/mol for the reaction. For this calculatio
    7·1 answer
  • What types of intermolecular interactions are present in pure substances composed of the each of the three molecules below:
    14·1 answer
  • Is drying wet clothes a physical or chemical change
    15·2 answers
  • 1. In the investigation of an unknown alcohol, there was a positive Jones test and a negative Lucas test. What deductions may be
    5·1 answer
  • Describe two tests that you can run to determine if something is a substance or a mixture.
    11·1 answer
  • Nitrogen gas effuses through an opening 1.59 times faster than an unknown gas.
    5·1 answer
  • Which of the following forms a molecular solid? Which of the following forms a molecular solid? C, graphite C10H22 CaO gold
    14·1 answer
  • What percentage of carpet is calcium carbonates?
    14·1 answer
  • Công thức toingr quát anken
    15·1 answer
  • Given that a for HCN is 6. 2×10^−10 at 25 °C. What is the value of b for cn− at 25 °C?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!