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d1i1m1o1n [39]
3 years ago
15

A scientist carries out a reaction twice. In Trial A, the scientist combines the reactants in a container. In Trial B, the scien

tist combines the reactants in the same container, but she also adds a catalyst. If everything else is the same about the two trials, what is most likely true about Trial B?
Chemistry
2 answers:
nirvana33 [79]3 years ago
8 0

Answer:

It will have a lower activation energy than Trial A.

Explanation:

Trail B will have a lower activation energy than trail A because in this trial the scientist adds a catalyst. Catalysts slow down reaction rates which will in turn mean a lower activation.

Paha777 [63]3 years ago
7 0
It would be C because It will have a lower activation energy than Trial A.
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A solution with a [H+] of 1.22x10-3M has a pH of _____________________.
Kryger [21]

Answer:

2.91

Explanation:

pH=-log(H3O+)

- Hope that helps! Please let me know if you need further explanation.

7 0
3 years ago
In this experiment we will be using a 0.05 M solution of HCl to determine the concentration of hydroxide (OH-) in a saturated so
gulaghasi [49]

<u>Answer:</u> The moles of hydroxide ions present in the sample is 0.0008 moles

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl.

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ca(OH)_2

We are given:

n_1=1\\M_1=0.05M\\V_1=16mL\\n_2=2\\M_2=?M\\V_2=36.0mL

Putting values in above equation, we get:

1\times 0.05\times 16=2\times M_2\times 36\\\\M_2=\frac{1\times 0.05\times 16}{2\times 36}=0.011M

To calculate the moles of hydroxide ions, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}

Molarity of solution = 0.011 M

Volume of solution = 36.0 mL

Putting values in above equation, we get:

0.011=\frac{\text{Moles of }Ca(OH)_2\times 1000}{36}\\\\\text{Moles of }Ca(OH)_2=\frac{0.011\times 36}{1000}=0.0004mol

1 mole of calcium hydroxide produces 1 mole of calcium ions and 2 moles of hydroxide ions.

Moles of hydroxide ions = (0.0004 × 2) = 0.0008 moles

Hence, the moles of hydroxide ions present in the sample is 0.0008 moles

8 0
2 years ago
Naming compounding<br> N2O
solniwko [45]

Answer:

Nitrogenous oxide/ nitrogen oxide

Explanation:

N2O is nitrogen oxide

6 0
2 years ago
Consider the nuclear equation below. Superscript 235 subscript 92 upper U right arrow superscript 4 subscript 2 upper H e. What
Leto [7]

Answer: The nuclide symbol of X is ^{231}_{90}\textrm{Th}

Explanation:

The given nuclear reaction is a type of alpha decay process. In this process, the nucleus decays by releasing an alpha particle. The mass number of the nucleus is reduced by 4 units and atomic number is also decreased by 2 units. The particle released is a helium nucleus.

The general equation representing alpha decay process is:

_{Z}^{A}\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\textrm{He}

For the given equation :

^{235}_{92}\textrm{U}\rightarrow ^{A}_{Z}\textrm{X}+^4_2\textrm{He}

As the atomic number and mass number must be equal on both sides of the nuclear equation:

^{235}_{92}\textrm{U}\rightarrow ^{231}_{90}\textrm{Th}+^4_2\textrm{He}

Thus the nuclide symbol of X is ^{231}_{90}\textrm{Th}

5 0
3 years ago
How many moles of hcl are required to neutralize aqueous solutions of these bases? 0.03 mol koh?
oksano4ka [1.4K]
 The  moles  of  HCl    are  required  to  neutralized    aqueous     solution     of  the   0.03  KoH

KOH  +  HCl  =  KCl  +   H2O


by   use  mole  ratio  between  KOH   to   HCl    which  is    1:1    the  moles    Of  HCl  is  also      0.03  moles
5 0
3 years ago
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