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d1i1m1o1n [39]
3 years ago
15

A scientist carries out a reaction twice. In Trial A, the scientist combines the reactants in a container. In Trial B, the scien

tist combines the reactants in the same container, but she also adds a catalyst. If everything else is the same about the two trials, what is most likely true about Trial B?
Chemistry
2 answers:
nirvana33 [79]3 years ago
8 0

Answer:

It will have a lower activation energy than Trial A.

Explanation:

Trail B will have a lower activation energy than trail A because in this trial the scientist adds a catalyst. Catalysts slow down reaction rates which will in turn mean a lower activation.

Paha777 [63]3 years ago
7 0
It would be C because It will have a lower activation energy than Trial A.
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Answer:

Option (B) 7

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C3H6O2(l) + O2(g) → CO2(g) + H2O(l)

To know the coefficient of O2 in the above equation, let us balance the equation.

The above equation can be balance as follow:

C3H6O2(l) + O2(g) → CO2(g) + H2O(l)

There are 3 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 3 in front of CO2 as shown below:

C3H6O2(l) + O2(g) → 3CO2(g) + H2O(l)

There are 6 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 3 in front of H2O as shown below:

C3H6O2(l) + O2(g) → 3CO2(g) + 3H2O(l)

There are a total of 4 atoms of O on the left side and a total of 9 atoms on the right side. It can be balance by putting 7/2 in front of O2 as show below:

C3H6O2(l) + 7/2O2(g) → 3CO2(g) + 3H2O(l)

Multiply through by 2

2C3H6O2(l) + 7O2(g) → 6CO2(g) + 6H2O(l)

Now, the equation is balanced.

From the balanced equation above, the coefficient of O2 is 7.

7 0
3 years ago
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