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tatyana61 [14]
3 years ago
15

Which family (group) of elements rarely forms chemical bonds with other elements?

Chemistry
1 answer:
Shkiper50 [21]3 years ago
8 0
Noble gases is the answer, I learned it in Chemisty class. Hope I helped :)
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A 0.229-g sample of an unknown monoprotic acid is titrated with 0.112 m naoh. the resulting titration curve is shown here. part
Kazeer [188]
It would be 0.341 because if you add 0.229 and 0.112 it will be 0.341
4 0
3 years ago
If there is a name/surname you can't make out due to a speaker's manner of speech, what are you supposed to do?
____ [38]

We can call a person by the word gentleman and Sir or from his/her real name.

If there is a name/surname you can't make out due to a speaker's manner of speech then I will call him gentleman or Sir or I will ask him his real name. Gentleman is a word that is used for noble person and Sir word is also used in order to give someone respect.

Call a person with his real name is also comes under the manner of speech so we can conclude that we can call a person by the word gentleman and Sir or from his/her real name.

Learn more about manner of speech here:

Learn more: brainly.com/question/26023566

6 0
3 years ago
A potential energy diagram is shown.
Vesna [10]

Answer:

25kJ

Explanation:

Given the initial energy to be 30kJ

The energy change from the initial energy to the peak energy = (65-30) kJ

= 35kJ

since the second energy change was a drop in energy it is regarded negative

= (55-65)

= -10kJ

Therefore total energy change

= (35-10)kJ

= 25kJ

5 0
2 years ago
Under certain conditions Argon gas diffuses at a rate of 3.2 cm per second under the same conditions an unknown gas diffuses at
kozerog [31]

Answer:

20 g/mol

Explanation:

We can use <em>Graham’s Law of diffusion</em>:

The rate of diffusion (<em>r</em>) of a gas is inversely proportional to the square root of its molar mass (<em>M</em>).

r = \frac{1 }{\sqrt{M}}

If you have two gases, the ratio of their rates of diffusion is

\frac{r_{2}}{r_{1}} = \sqrt{\frac{M_{1}}{M_{2}}}

Squaring both sides, we get

(\frac{r_{2}}{r_{1}})^{2} = \frac{M_{1}}{M_{2}}

Solve for <em>M</em>₂:

M_{2} = M_{1} \times (\frac{r_{1}}{r_{2}})^{2}

M_{2} = \text{39.95 g/mol} \times (\frac{\text{3.2 cm/s}}{\text{4.5 cm/s}})^{2}= \text{39.95 g/mol} \times (0.711 )^{2}

= \text{39.95 g/mol} \times 0.506 = \textbf{20 g/mol}

7 0
3 years ago
what information can a foliated metamorphic rock provide you about the conditions under which it formed
uysha [10]
The information that a foliated metamorphic rock provide about the conditions it was formed under are:(for many diffrent rocks like Phyllite and Amphibolite) 
you can tell by its features like if its smooth and sleek  or if its rough and bumpy those physical features.
3 0
3 years ago
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