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yuradex [85]
2 years ago
5

when 4.73g of solid was heated, the residue weighed 4.10g 320 cubic centimetre of gas( at RTP) was evolved. calculate the molecu

lar mass of the gas​
Chemistry
1 answer:
Eddi Din [679]2 years ago
8 0

Answer:

48 g/mol

Explanation:

Step 1: Calculate the mass of the gas (m)

According to the law of conservation of mass, the mass of the solid before the decomposition must be equal to the sum of the masses of the solid residue and the gas

mSolid = mResidue + mGas

mGas = mSolid - mResidue = 4.73 g - 4.10 g = 0.63 g

Step 2: Convert 320 cm³ to L

We will use the conversion factor 1 L = 1000 cm³.

320 cm³ × 1 L/1000 cm³ = 0.320 L

Step 3: Calculate the moles of gas (n)

The gas is at room temperature (298.15 K) and room pressure (1 atm). We can calculate the moles of gas using the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 1 atm × 0.320 L/(0.0821 atm.L/mol.K) × 298.15 K = 0.0131 mol

Step 4: Calculate the molecular mass of the gas (M)

We will use the following expression.

M = m/n = 0.63 g/0.0131 mol = 48 g/mol

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Explanation:

The flame test is a widely used qualitative analysis method to identify the presence of a certain chemical element in a sample. To carry it out you must have a gas burner. Usually a Bunsen burner, since the temperature of the flame is high enough to carry out the experience (a wick burner with an alcohol tank is not useful). The flame temperature of the Bunsen burner must first be adjusted until it is no longer yellowish and has a bluish hue to the body of the flame and a colorless envelope. Then the tip of a clean platinum or nichrome rod (an alloy of nickel and chromium), or failing that of glass, is impregnated with a small amount of the substance to be analyzed and, subsequently, the rod is introduced into the flame, trying to locate the tip in the least colored part of the flame.

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<h3>Further explanation</h3>

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Learn more about moles here:

brainly.com/question/26416088

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