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3 years ago

What is the value of x?

Mathematics

2 answers:

kherson [118]3 years ago

6 0

Answer:

61 degrees.

Step-by-step explanation:

Any triangle's interior angles must add up to 180. 67 + 52 = 119. 180 - 119 = 61.

kkurt [141]3 years ago

3 0

Answer:

The value of x is 61 degrees

Step-by-step explanation:

Becasue a triangle can have a total degrees of 180 and if we add the degrees of B and C you get 119 and if you subtract that from 180 you get 61, therefore 61 degrees is the value of x

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5 divide 15x 15squared

Goryan [66]

Answer:

Step-by-step explanation:

(5 /15) x (15 squared = 75

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2 years ago

What is the length of the leg in a right triangle whose hypotenuse is 13 and other leg is 12.

Talja [164]

It is 5 because you have to do 12 squared minus 13 squared and then square root that which equals 5

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3 years ago

Read 2 more answers

Suppose j varies jointly with g and v, and j=2 when g=4 and v=3. <br> Find j when g=8 and v=9.

vladimir2022 [97]

Answer:

$j=12$

Step-by-step explanation:

we know that

In a join variation, If j varies jointly with respect to g and v, the equation will be of the form $j = kgv$

where k is a constant

step 1

Find the value of k

we have

j=2,g=4,v=3

substitute and solve for k

$2 = k(4)(3)$

$2 = 12k$

$k=\frac{1}{6}$

The equation is equal to

$j=\frac{1}{6}gv$

step 2

Find the value of j when g=8,v=9

substitute the values in the equation and solve for j

$j=\frac{1}{6}(8)(9)$

$j=12$

3 0

2 years ago

a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you

aniked [119]

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that $P(A) = 0.8$

If you have passed subject A, the probability of passing subject B is 0.8.

This means that $P(B|A) = 0.8$

Find the probability that the student passes both subjects?

This is $P(A \cap B)$ . So

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

$P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64$

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

$p = P(A) + P(B) - P(A \cap B)$

Considering $P(B) = 0.7$ , we have that:

$p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86$

0.86 = 86% probability that the student passes at least one of the two subjects

3 0

3 years ago

3) What happens when you add a pair of opposites together?

Andrei [34K]

The sum of any integer and its opposite is equal to zero

Hope this helps :)

8 0

2 years ago