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Gnesinka [82]
3 years ago
11

A space shuttle travels in orbit at 21,000 km/hr. how far will it travel in 5 hr

Physics
1 answer:
Radda [10]3 years ago
3 0

Answer:

Explanation:

distance = speed * time  

distance = 21000 * 5 = 105000 km

please mark me as Brainliest

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A cyclist acceleration from 0m/s to 8m/s in 3second. what is his acceleration?​
umka2103 [35]

Answer:

2.66 m/s² .

Explanation:

Initial velocity , u = 0 m/s

Final Velocity , v = 8 m/s

Time Taken , t = 3 s

So , Acceleration = (v-u)/t = (8 m/s - 0 m/s) /3 sec . = 8/3 m/s² = 2.66 m/s²

4 0
3 years ago
If you want to double the kinetic energy of a gas molecule, by what factor must you increase its momentum?A) 16B) 2^(1/2)
worty [1.4K]

Answer: \sqrt{2}

The linear momentum p is given by the following equation:

p=m.v   (1)

Where m is the mass and v the velocity.

On the other hand, the kinetic energy K is given by:

K=\frac{p^{2}}{2m}   (2)

Which is the same as:

K=\frac{1}{2}m.v^{2}

Now, if we double the kinetic energy, equation (2) changes to:

2K=2\frac{p^{2}}{2m}  

2K=\frac{p^{2}}{m}   (3)

So, if we want to obtain the kinetic energy as shown in (3), the only option that works is increasing momentum by a factor of \sqrt{2} or 2^{1/2}:

Applying this in (2):

K=\frac{(\sqrt{2}p)^{2}}{2m}

K=\frac{(2p)^{2}}{2m}

K=\frac{p^{2}}{m}>>>As we can see, this equation is the same as equation (3)

Therefore, the correct answer is B

3 0
3 years ago
A sprinter who is running a 200-m race travels the second 100 m in much less time than the first 100m because
Harrizon [31]

Answer:

He is warmed up now

Explanation:

His muscles are better and stretched now

3 0
3 years ago
Read 2 more answers
Whitt is considered a prokaryotic cell
djverab [1.8K]
Microorganisms and all other living organisms are told to be procarotics
6 0
3 years ago
Unpolarized light with intensity I0I0I_0 is incident on an ideal polarizing filter. The emerging light strikes a second ideal po
Montano1993 [528]

Answer:

A) I = Io 0.578,   B) he light that leaves the polarized is completely polarized, being perpendicular to the axis of the second filter

Explanation:

A) Light passing through a polarizer must comply with the / bad law

          I = Io cos2 tea

Where is at the angle of the polarizer and incident light

          I = Io cos2 45

         I = Io 0.578

Therefore the beam intensity is 0.578 of the incident intensity

.B) the light that leaves the polarized is completely polarized, being perpendicular to the axis of the second filter

3 0
4 years ago
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