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3 years ago

How does an atom change if all of its electrons are removed?

2 answers:

6 0

Because the transfer of electrons is called an ion, and also, they are being lost, they atom will become positively charged. The Ion will lose electrons and become a cation.

Answer: The atom becomes positively charged.

Tanzania [10]3 years ago

4 0

The correct answer to the question is : C) The atom becomes positively charged.

EXPLANATION :

An isolated atom is electrically neutral. It is so because the total number of electrons is equal to total number of protons.

As per the question, all the electrons from the atom are removed.

We know that electron is a negatively charged particle, and proton is a positively charged particle.

When all the electrons are removed from the atom, the atom contains only protons and neutrons. The neutron is a neutral nucleon. Hence, the atom will be positively charged due to the excess number of protons.

Hence, the correct answer is that atom will be positively charged.

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Using component notation, enter the vector B⃗ B→B_vec in the answer box. Enter your answer as a pair of vector components, separ

Tomtit [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value is $\vec B = 2, -3$

Explanation:

Looking at the graph in the diagram we see each unit is equal to 1 both in the x axis and in the y- axis

Now the value of B along the x axis is

$B_x = 2$

and along the y axis the value is

$B_y = -3$

Hence the vector B is

$\vec B =(B_x , B_y)= ( 2, -3)$

8 0

3 years ago

A student is investigating potential and kinetic energy by stretching a spring across a table when the student lets go the sprin

nikitadnepr [17]

Answer: could be B.

Explanation:

7 0

2 years ago

If the star Sirius emits 23 times more energy than the Sun, why does the Sun appear brighter in the sky?

Ganezh [65]

Answer:

As b ∝ (L/r²) and

the distance of the sun from the earth is 0.00001581 light years

and

the distance of the Sirius from the earth is 8.6 light years

hence,

the Sun appear brighter in the sky

Explanation:

The brightness (b) is directly proportional to the Luminosity of the star (L) and inversely proportional to the square of the distance between the star and the observer (r).

thus, mathematically,

b ∝ (L/r²)

now,

given

L for sirius is 23 times more than the sun i.e 23L

now,

the distance of the sun from the earth is 0.00001581 light years

and

the distance of the Sirius from the earth is 8.6 light years

thus,

using the the relation between conclude that the value of brightness for the Sirius comes very very low as compared to the value for brightness for the Sun.

hence, the sun appears brighter

5 0

3 years ago

A stone with a mass m is dropped from an airplane that has a horizontal velocity v at a height h above a lake. If air resistance

seropon [69]

Answer: Option B. R = (1/2)gt^2

Explanation:

S = R (horizontal distance)

V^2 = 2gS

V^2 = 2gR

R = V^2 / 2g

But V = gt

R = (gt)^2 / 2g

R = (g^2 x t^2) / 2g

R = gt^2 / 2

But t^2 = 2h/g

R = ( g x 2h/g) / 2

R = h

But h = (1/2)gt^2

R = h = (1/2)gt^2

4 0

3 years ago

In pairs figure-skating competition, a 65-kg man and his 45-kg female partner stand facing each other both at rest on the ice. I

Lina20 [59]

Answer:

The final velocity of her partner is approximately -1.04 m/s or 1.04 m/s in the opposite direction to her direction of motion

Explanation:

The given parameters are;

The mass of the man, m₁ = 65 kg

The mass of the woman, m₂ = 45 kg

Taking the relative initial velocity of the man and the woman as 0 m/s, we have;

The initial velocity of the man, v₁₁ = 0 m/s

The initial velocity of the man, v₁₂ = 0 m/s

The final velocity of the woman, v₂₂ = 1.5 m/s

The final velocity of the man = v₂₁

Therefore, we have, by the conservation of momentum principle;

The total initial momentum = The total final momentum

Which gives;

m₁ × v₁₁ + m₂ × v₁₂ = m₁ × v₂₁ + m₂ × v₂₂

Substituting the known values;

65 × 0 + 45 × 0 = 65 × v₂₁ + 45 × 1.5

∴ 65 × v₂₁ + 45 × 1.5 = 0

45 × 1.5 = - 65 × v₂₁

v₂₁ = 45 × 1.5/(-65) ≈ -1.04 m/s

The final velocity of the man, her partner = v₂₁ ≈ -1.04 m/s.

6 0

3 years ago