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3 years ago

How does an atom change if all of its electrons are removed?

2 answers:

6 0

Because the transfer of electrons is called an ion, and also, they are being lost, they atom will become positively charged. The Ion will lose electrons and become a cation.

Answer: The atom becomes positively charged.

Tanzania [10]3 years ago

4 0

The correct answer to the question is : C) The atom becomes positively charged.

EXPLANATION :

An isolated atom is electrically neutral. It is so because the total number of electrons is equal to total number of protons.

As per the question, all the electrons from the atom are removed.

We know that electron is a negatively charged particle, and proton is a positively charged particle.

When all the electrons are removed from the atom, the atom contains only protons and neutrons. The neutron is a neutral nucleon. Hence, the atom will be positively charged due to the excess number of protons.

Hence, the correct answer is that atom will be positively charged.

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2 years ago

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2 years ago

A motorcycle traveling at a speed of 44.0 mi/h needs a minimum of 44.0 ft to stop. If the same motorcycle is traveling 79.0 mi/h

Tasya [4]

Answer:

141.78 ft

Explanation:

When speed, u = 44mi/h, minimum stopping distance, s = 44 ft = 0.00833 mi.

Calculating the acceleration using one of Newton's equations of motion:

$v^2 = u^2 + 2as\\\\v = 0 mi/h\\\\u = 44 mi/h\\\\s = 0.00833 mi\\\\=> 0^2 = 44^2 + 2 * a * 0.00833\\\\=> 1936 = -0.01666a\\\\a = -116206.48 mi/h^2 or -14.43 m/s^2$

Note: The negative sign denotes deceleration.

When speed, v = 79mi/h, the acceleration is equal to when it is 44mi/h i.e. -116206.48 mi/h^2

Hence, we can find the minimum stopping distance using:

$v^2 = u^2 + 2as\\\\v = 0 mi/h\\\\u = 79 mi/h\\\\a = -116206.48 mi/h\\\\=> 0^2 = 79^2 + (2 * -116206.48 * s)\\\\6241 = 232412.96s\\\\s = \frac{6241}{232412.96} \\\\s = 0.0268531 mi = 141.78 ft$

The minimum stopping distance is 141.78 ft.

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2 years ago