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2 years ago

How does an atom change if all of its electrons are removed?

2 answers:

6 0

Because the transfer of electrons is called an ion, and also, they are being lost, they atom will become positively charged. The Ion will lose electrons and become a cation.

Answer: The atom becomes positively charged.

Tanzania [10]2 years ago

4 0

The correct answer to the question is : C) The atom becomes positively charged.

EXPLANATION :

An isolated atom is electrically neutral. It is so because the total number of electrons is equal to total number of protons.

As per the question, all the electrons from the atom are removed.

We know that electron is a negatively charged particle, and proton is a positively charged particle.

When all the electrons are removed from the atom, the atom contains only protons and neutrons. The neutron is a neutral nucleon. Hence, the atom will be positively charged due to the excess number of protons.

Hence, the correct answer is that atom will be positively charged.

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If a total force exerted by water in a container with a bottom area of 3 square meters is 900 newtons, what's the water pressure

anyanavicka [17]

<h3>Answer:</h3>

p=300 Pa

<h3>Explanation:</h3>

_______________

S=3 m²

F=900 N

_______________

p - ?

_______________

p=F/S=900 N / 3 m² = 300 Pa

6 0

1 year ago

A swinging pendulum has a total energy of <img src="https://tex.z-dn.net/?f=E_i" id="TexFormula1" title="E_i" alt="E_i" align="a

Zolol [24]

Answer:

$\frac{E_{2}}{E_{1}} \approx 1 -\frac{3\theta}{1-\theta}$ (for small oscillations)

Explanation:

The total energy of the pendulum is equal to:

$E_{1} = m\cdot g \cdot (1-\cos \theta)\cdot L$

For small oscillations, the equation can be re-arranged into the following form:

$E_{1} \approx m\cdot g \cdot (1-\theta) \cdot L$

Where:

$\theta = \frac{A}{L^{2}}$ , measured in radians.

If the amplitude of pendulum oscillations is increase by a factor of 4, the angle of oscillation is $4\theta$ and the total energy of the pendulum is:

$E_{2} \approx m\cdot g \cdot (1-4\theta)\cdot L$

The factor of change is:

$\frac{E_{2}}{E_{1}} \approx \frac{1 - 4\theta}{1-\theta}$

$\frac{E_{2}}{E_{1}} \approx 1 -\frac{3\theta}{1-\theta}$

3 0

2 years ago

What do you observe as you immerse the empty jug in a bucket which contains water? Explain why you observe this phenomenon.

liraira [26]

Answer:

The jug drowns because the density of the jug is more than that of the density of water.

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2 years ago

Read 2 more answers

a student calculates experimentally the value of density of an iron as 4.4 gcm³. if the actual density of an iron is 7.6 gcm³, c

ser-zykov [4K]

Hola!

Percentage Error is a measurement of the discrepancy between an observed and a true, or accepted value.

[ refer the attachment. ]

According to Question,

% error = $\frac{7.4 - 7.6}{7.6}$ × 100

= 2.631 % = 2.7 % (approximately.)

hope it helps!

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2 years ago

6) A map in a ship’s log gives directions to the location of a buried treasure. The starting location is an old oak tree. Accord

kiruha [24]

Answer:

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Explanation:

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2 years ago