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Rina8888 [55]
3 years ago
6

47. the beam is supported by two rods ab and cd that have cross-sectional areas of 12mm^2 and 8mm^2, respectively. determine the

position d of the 6-kn load so that the average normal stress in each rod is the same.
Physics
1 answer:
Ugo [173]3 years ago
8 0

Let the beam is of length L

Now the stress on both the end is same

now we can say that torque on the beam due to two forces must be zero

N_1* x =  N_2* (L - x)

also we know that stress at both ends are same

\frac{N_1}{12} = \frac{N_2}{8}

2*N_1 = 3*N_2

Now from two equations we have

\frac{3}{2}N_2*x = N_2* (L - x)

solving above equation we have

x = \frac{2}{5}L

<em>so the load is placed at distance 0.4L from the end of 12 mm^2 area</em>

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In the given problem, we say various information's that are going to help us reach the ultimate answer to the question. Let us first write the information's that have been presented in front of us.
Mass of the car = 2000 kg
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Now we already know the equation for calculating the centripetal force and that is
Centripetal Force = [mass * (velocity)^2]/Radius
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