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Rina8888 [55]
3 years ago
6

47. the beam is supported by two rods ab and cd that have cross-sectional areas of 12mm^2 and 8mm^2, respectively. determine the

position d of the 6-kn load so that the average normal stress in each rod is the same.
Physics
1 answer:
Ugo [173]3 years ago
8 0

Let the beam is of length L

Now the stress on both the end is same

now we can say that torque on the beam due to two forces must be zero

N_1* x =  N_2* (L - x)

also we know that stress at both ends are same

\frac{N_1}{12} = \frac{N_2}{8}

2*N_1 = 3*N_2

Now from two equations we have

\frac{3}{2}N_2*x = N_2* (L - x)

solving above equation we have

x = \frac{2}{5}L

<em>so the load is placed at distance 0.4L from the end of 12 mm^2 area</em>

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The torque exerted by a crowbar on an object increases with increased _______.
Fofino [41]

Answer:

force and leverage distance

Explanation:

the formula for torque if = force x distance

(the distance above is the leverage distance on the crow bar)

therefore if there is an increase in either the torque or the leverage distance, or both, the torque exerted by the crow bar also increases.

for example

  • lets assume a force of 5 n is applied on the crow bar with a leverage distance of 2 m.

        the torque = 5 x 2 = 10 N.m

  • but if the force was increased to 7 N

        torque = 7 x 2 = 12 N.m

from the illustration above, we can see that the torque increased with an increase in force. There would also be an increase in torque if the distance were to be increased.

3 0
3 years ago
A cue ball, moving with 9.0 N·s of momentum strikes the nine-ball at rest. The nine-ball moves off with 2.0 N·s in the original
lisov135 [29]

Answer:

P = 7.28 N.s

Explanation:

given,

initial momentum of cue ball in x- direction,P₁ = 9 N.s

momentum of nine ball in  x-  direction, P₂ = 2 N.s

momentum in perpendicular direction i.e. y - direction,P'₂ = 2 N.s

momentum of the cue after collision = ?

using conservation of momentum

in x- direction

P₁ + p = x  + P₂

p is the initial momentum of the nine balls which is equal to zero.

9 + 0  = x  + 2

x = 7 N.s

momentum in x-direction.

equating along y-direction

P'₁ + p = y + P'₂

0 + 0 = y + 2

y = -2 N.s

the momentum of the cue ball after collision is equal to resultant of the momentum .

P = \sqrt{x^2+y^2}

P = \sqrt{7^2+(-2)^2}

      P = 7.28 N.s

the momentum of the cue ball after collision is equal to P = 7.28 N.s

7 0
3 years ago
During the spin cycle of your clothes washer, the tub rotates at a steady angular velocity of 31.7 rad/s. Find the angular displ
Crank

Answer:

\Delta \theta = 3116.11\,rad and \Delta \theta = 495.944\,rev

Explanation:

The tub rotates at constant speed and the kinematic formula to describe the change in angular displacement (\Delta \theta), measured in radians, is:

\Delta \theta = \omega \cdot \Delta t

Where:

\omega - Steady angular speed, measured in radians per second.

\Delta t - Time, measured in seconds.

If \omega = 31.7\,\frac{rad}{s} and \Delta t = 98.3\,s, then:

\Delta \theta = \left(31.7\,\frac{rad}{s} \right)\cdot (98.3\,s)

\Delta \theta = 3116.11\,rad

The change in angular displacement, measured in revolutions, is given by the following expression:

\Delta \theta = (3116.11\,rad)\cdot \left(\frac{1}{2\pi} \frac{rev}{rad} \right)

\Delta \theta = 495.944\,rev

6 0
3 years ago
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miv72 [106K]

Answer:

v_{A}=v_{Ai}

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The total momentum of the system must conserve by the law of momentum conservation.

p_b=p_a\\\\m_Av_{Ai}+m_Bv_{Bi}=m_Av_{A}+m_Bv_{B}    ( 1 )

If you consider the shock between the ball and the truck as totally elastic, and also if the truck is much more massive than the ball, you can assume that the truck does not move when the ball hits it.

Then the truck is always at rest

Hence, you have in the expression ( 1 ):

m_Av_{Ai}+0=m_Av_{A}+0\\\\v_{Ai}=v_{A}

3 0
3 years ago
Water can be described in a variety of ways. Which of the following statements describes a chemical property of water?
kherson [118]
The answer is C I think
4 0
3 years ago
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