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sergiy2304 [10]
4 years ago
9

How many milliliters of a .89 M solution of HCl is needed to have 1.3 mole of HCl?

Chemistry
2 answers:
gayaneshka [121]4 years ago
8 0
V=250.mL hope this helps
Artemon [7]4 years ago
6 0
Molarity = Moles/Liter
We then set up this equation: (0.89 moles/1 liter) *x liters = 1.3 moles
Rearrange the equation:  (1 liter/0.89 moles) * 1.3 moles = 1.461 liters
Convert liters to milliliters: 1.461L *(1000ml/1L) = 1460.7 ml
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<h3>What is tert-butyl chloride?</h3>

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Answer:

HCOOH(aq) + OH-(aq) —> HCOO-(aq) + H2O(l)

Explanation:

HCOOH is a weak acid and so will not ionised completely in solution.

KOH is a strong base and will ionised completely as shown below

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The overall reaction can be written as follow:

HCOOH(aq) + K+(aq) + OH-(aq) —> HCOO-(aq) + K+(aq) + H2O(l)

Cancel out the K+ to obtain the net ionic equation as shown below

HCOOH(aq) + OH-(aq) —> HCOO-(aq) + H2O(l)

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