In the United States, fire codes are developed primarily by two model code organizations, the International Code Council (ICC) and the National Fire Protection Association (NFPA).
Choose a quality one, and don't use it as necessary
Answer:
Steps:
1. Create a text file that contains blade diameter (in feet), wind velocity (in mph) and the approximate electricity generated for the year
2. load the data file for example, in matlab, use ('fileame.txt') to load the file
3. create variables from each column of your data
for example, in matlab,
x=t{1}
y=t{2}
4. plot the wind velocity and electricity generated.
plot(x, y)
5. Label the individual axis and name the graph title.
title('Graph of wind velocity vs approximate electricity generated for the year')
xlabel('wind velocity')
ylabel('approximate electricity generated for the year')
What you mean?? .!.!.!.!!.
Answer:
![\frac{\delta p }{l} = 30.4 lb/ft^3](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cdelta%20p%20%7D%7Bl%7D%20%3D%2030.4%20lb%2Fft%5E3)
Explanation:
Given data:
flow rate = 10 gallon per minute = 0.0223 ft^3/sec
diameter = 0.75 inch
we know discharge is given as
Q = VA
solve for velocity V = \frac{Q}{A}[/tex]
![V = \frac{0.223}{\frac{\pi}{4} \frac{0.75}{12}}](https://tex.z-dn.net/?f=%20V%20%3D%20%5Cfrac%7B0.223%7D%7B%5Cfrac%7B%5Cpi%7D%7B4%7D%20%5Cfrac%7B0.75%7D%7B12%7D%7D)
V = 7.27 ft/sec
we know that Reynold number
![Re = \frac{VD}{\nu}](https://tex.z-dn.net/?f=Re%20%3D%20%5Cfrac%7BVD%7D%7B%5Cnu%7D)
![Re = \frac{7.27 \times \frac{0.75}{12}}{1.21\times 10^{-5}}](https://tex.z-dn.net/?f=Re%20%3D%20%5Cfrac%7B7.27%20%5Ctimes%20%5Cfrac%7B0.75%7D%7B12%7D%7D%7B1.21%5Ctimes%2010%5E%7B-5%7D%7D)
![Re = 3.76 \times 10^4](https://tex.z-dn.net/?f=Re%20%3D%203.76%20%5Ctimes%2010%5E4%20)
calculate the
ratio to determine the fanning friction f
![\frac{\epsilon }{D} = \frac{0.0005}{\frac{0.75}{12}} = 0.008](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cepsilon%20%7D%7BD%7D%20%3D%20%5Cfrac%7B0.0005%7D%7B%5Cfrac%7B0.75%7D%7B12%7D%7D%20%3D%200.008)
from moody diagram f value corresonding to Re and
is 0.037
for horizontal pipe
![\delta p = \frac{f l \rho v^2}{2D}](https://tex.z-dn.net/?f=%5Cdelta%20p%20%3D%20%5Cfrac%7Bf%20l%20%5Crho%20v%5E2%7D%7B2D%7D)
![\frac{\delta p }{l} = \frac{1 \times 0.037 \times 1.94 \times 7.27}{\frac{0.75}{12}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cdelta%20p%20%7D%7Bl%7D%20%3D%20%5Cfrac%7B1%20%5Ctimes%200.037%20%5Ctimes%201.94%20%5Ctimes%207.27%7D%7B%5Cfrac%7B0.75%7D%7B12%7D%7D)
where 1.94 slug/ft^3is density of water
![\frac{\delta p }{l} = 30.4 lb/ft^3](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cdelta%20p%20%7D%7Bl%7D%20%3D%2030.4%20lb%2Fft%5E3)