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d1i1m1o1n [39]
4 years ago
10

What properties are those that describe what happens when a substance reacts with another substance? catalyst properties chemica

l properties physical properties mineral properties?
Chemistry
2 answers:
8090 [49]4 years ago
5 0
............ chemical properties.........
Liono4ka [1.6K]4 years ago
5 0

Answer:

Chemical properties,

Explanation:

Let us understand all the given terms

a) catalyst properties: this is the property of a substance by virtue of which it helps to modulate the rate of reaction, and itself remains unconsumed during the reaction (does not react). Example : enzymes

b) chemical properties: this is the property of a substance by virtue of which it reacts with another substance to give a new product of different structure, bonding, chemical and physical properties.

Example : hydrogen reacts with oxygen to give water.

So here the hydrogen is undergoing reaction with oxygen and this is chemical property of hydrogen.

c) Physical properties: This is the property which is related to the nature of a substance to exit in nature. for example hydrogen is a gas is its physical property not chemical.

d) mineral properties: It  is again a kind of physical property.

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The normal freezing point of a certain liquid
stepladder [879]

Answer : The molal freezing point depression constant of X is 4.12^oC/m

Explanation :  Given,

Mass of urea (solute) = 5.90 g

Mass of X liquid (solvent) = 450.0 g

Molar mass of urea = 60 g/mole

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{\text{Mass of urea}\times 1000}{\text{Molar mass of urea}\times \text{Mass of X liquid}}

where,

\Delta T_f = change in freezing point

\Delta T_s = freezing point of solution = -0.5^oC

\Delta T^o = freezing point of liquid X= 0.4^oC

i = Van't Hoff factor = 1  (for non-electrolyte)

K_f = molal freezing point depression constant of X = ?

m = molality

Now put all the given values in this formula, we get

[0.4-(-0.5)]^oC=1\times k_f\times \frac{5.90g\times 1000}{60g/mol\times 450.0g}

k_f=4.12^oC/m

Therefore, the molal freezing point depression constant of X is 4.12^oC/m

4 0
3 years ago
“STEPS TO BE TAKEN TO REDUCE FUEL CONSUMPTION AT HOME
Ipatiy [6.2K]

   Drive only when needed. The best way to reduce the fuel consumption is to simply drive your car less. Drive your car only when you really need to. If you only need to travel a few blocks, consider walking or even riding a bicycle. Not only will you save money at the pump, the exercise will certainly do you some good

   Make sure the gas cap is on tight. One reason you may not be getting the mileage you expect is because there isn't as much gas in your tank as you think. 147 million gallons of gas were lost last year due to evaporation. Why did it evaporate? The gas cap was not on tight. So just make sure it is tight, and it will enable you to keep all the gas you pay for

   Avoid idling. When you do need to drive your car, make sure you avoid idling whenever possible. When your car is running, but not moving, your gas mileage is absolute zero. So if your car will remain stationary for more than a minute or so, switch the engine off. However, only do this when it is safe to do so

   Accelerate and break steadily. While driving, always apply steady and consistent pressure to your car's accelerator pedal. A heavy foot will always result in reduced gas mileage and poor fuel consumption

   Drive the speed limit. Always try to drive at or near the speed limit. The optimal traveling speed for every make and model vehicle is different. However, the faster you drive, the worse your gas mileage and fuel consumption will be. Drive as fast as you need to in order to maintain a safe driving speed. But, save highway driving speeds for the highway and not around town

   Coast when possible. Constantly accelerating and braking only wastes fuel and reduces your car's fuel consumption. So, whenever possible, coast and avoid burning excess fuel. This takes a little practice, but can be a great way to increase the fuel economy of your vehicle

   Use cruise control on the highways. Cruise control means that your car will be going at a constant velocity, which means there is no acceleration. No acceleration reduces the amount of work your engine does, and therefore it uses less gas. You should set your cruise control at the speed limit, because 55 miles per hour is the perfect speed for maximum fuel efficiency

   Make your car more aerodynamic. You can do so by removing the roof racks on top of the car, and also by decreasing the weight of the car by taking out unneeded items

   Keep the windows closed. The more aerodynamic your vehicle remains, the better your car's fuel efficiency. Keeping your windows down while driving creates more drag and wind resistance for your automobile. If you are driving at speeds of less than 35 mph, it is usually okay to keep the windows down. However, at higher speeds, you should keep the windows up order to reduce drag and improve fuel consumption

   Minimize air conditioning. There will be times, of course, when summer heat will cause you to use the air conditioning system. However, use the AC in moderation. If you need to choose between keeping your windows rolled down or using the AC at high speeds, use the air conditioning on a low setting

   Replace dirty air filters. Dirty air filters cause your car's engine to work much harder than it has to and always results in poor fuel economy. So, make sure you follow the manufacturer's recommendation for periodically changing out the air filter. A clean air filter allows your engine to perform more efficiently and also helps you save money at the pump

   Maintain proper tire inflation. Check your car owner's manual and always ensure your tires are inflated to the proper air pressure level. Improperly inflated tires can reduce your car's fuel economy by up to five percent in some cases. This is quite simply a complete waste of fuel and money

   Reduce weight in the vehicle. Get rid of any unnecessary items in your car's trunk or other areas of the vehicle. For every 100 pounds of weight in the vehicle, your car's fuel economy decreases by about one or two percent. By making sure your vehicle remains as light as possible, you can improve the fuel consumption of your vehicle and save money on your fuel bill

 

Sorry it's really long :P but hope this helped

4 0
3 years ago
!!29 POINTS!! PLS HELP ASAP
ICE Princess25 [194]

Answer:

The person who just wanted points is annoying

Explanation:

WHY WOULD YOU DO THAT

8 0
3 years ago
A liquid solvent is added to a flask containing an insoluble solid. The total volume of the solid and liquid together is 80.0 mL
Lyrx [107]

Answer:

111.44 g

Explanation:

We'll begin by calculating the volume of the solvent. This can be obtained as follow:

Mass of solvent = 21 g

Density of solvent = 0.865 g/mL.

Volume of solvent =?

Density = mass /volume

0.865 = 21 /volume of solvent

Cross multiply

0.865 × volume of solvent = 21

Divide both side by 0.865

Volume of solvent = 21 / 0.865

Volume of solvent = 24.28 mL

Next, we shall determine the volume of the solid. This can be obtained as follow:

Volume of solvent + solid = 80.0 mL.

Volume of solvent = 24.28 mL

Volume of solid =?

Volume of solid = (Volume of solvent + solid) – (Volume of solvent)

Volume of solid = 80 – 24.28

Volume of solid = 55.72 mL

Finally, we shall determine the mass of the solid. This can be obtained as follow:

Density of solid = 2.00 g/mL.

Volume of solid = 55.72 mL

Mass of solid =.?

Density = mass / volume

2 = mass of solid / 55.72

Cross multiply

Mass of solid = 2 × 55.72

Mass of solid = 111.44 g

Therefore, the mass of the solid is 111.44 g

8 0
3 years ago
An example of a disaccharide is saccharin-aspartame molecule True False
Flura [38]
I think is False! Because it is not example of a disaccharide it is not saccharin-aspartame molecule.
6 0
3 years ago
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