Answer:
1.After 11 hours, the cruise ship will be _233.75__nautical miles from the lighthouse.
2.At the start of the journey, the cruise ship was _10.5__
nautical miles from the lighthouse.
3.The cruise ship is traveling at a speed of_21.25_ nautical miles per hour.
Explanation:
Distance covered in 2 hours= 95.5-53NM
=42.5NM
therefore,
put value of distance and time in equation (1)
therefore,
speed=21.25NM/hour
Therefore distance covered in 11 hours= speed* time
=233.75NM
2. Since distance covered in 2 hours is 42.5
therefore, at starting of the journey the cruise distance from light house is
= 53NM-42.5NM
=10.5NM
3. Distance covered in 2 hours= 95.5-53NM
=42.5NM
therefore,
put value of distance and time in equation (1)
therefore,
speed=21.25NM/hour
Therefore Cruise ship is traveling at speed of 21.25NM/hour
F = ma
double f and m gives
(2f) = (2m)a
notice a is unchanged = 2.2
m/s^2
Answer:
Part A: D
Part B: W = Qh - Qc
Part C: e = 1 - Qc/Qh
Explanation:
The heat engine is the engine that transforms heat (Q) in work (W), and by the second law of the thermodynamics, its efficiency can not be 100%, it means that some heat must be dissipated.
Part A:
The engine works with two sources of heat, one hot (Qh) at a hot temperature (Th) and another cold (Qc) at a cold temperature (Tc). It is necessary so, the hot source will give energy to the fluid of the engine, and the cold source will be the source where these heat will dissipate and the fluid will return to its original temperature. So,
Qh > Qc, and Th > Tc
Part B:
The ideal heat engine is the one that can use the most amount of heat to transform it at work. It is characterized by Qh/Qc = Th/Tc.
The work is the useful energy, so it is the total heat (Qh) less the heat dissipated (Qc):
W = Qh - Qc
Part C:
The effiency is the useful energy divided by the total energy. Because W = Qh - Qc:
e = W/Qh
e = (Qh - Qc)/Qh
e = Qh/Qh - Qc/Qh
e = 1 - Qc/Qh
(since you asked for basic understanding only, I am not including actual calculations. Please let me know in the comments section if you wish to verify your solution(s))
For (b): Use the formula for distance (s) made during an accelerated motion:
with v_0 and s_0 being the initial velocity and distance, both 0 in this case, and with "a" denoting the acceleration, in this case solely due to gravitational acceleration so: "g."
You are given the distance made, namely 10 m, and the duration t (0.88s) and so using the formula above you can solve for g.
For (c), to determine the final velocity at time 0.88s use the formula for the instantaneous velocity of an accelerated motion
(velocity at time t) = (acceleration) x (time)
again, with acceleration due to gravity, i.e., a = g and with g as determined under (b).
If my calculation is correct, this mystery planet could be the Jupiter.
E=F*d/2 = M*g*d/2 = 25kg * 9.8 N/kg *0.65m / 2 = 79.625J