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Studentka2010 [4]
4 years ago
7

1. A scientific hypothesis can become a theory if ______.

Chemistry
2 answers:
OLga [1]4 years ago
8 0
1) - it can become a theory if the hypothesis is <span>tested extensively and competing hypotheses are eliminated - other options are not enough


2) This is a hypothesis. A theory is basically almost an established truth, which can still be changed with new data, but which as far as we know is true.</span>
Dominik [7]4 years ago
4 0

1) The answer is: B) the hypothesis is tested extensively and competing hypothesis are eliminated.

Theory is a tested, unifying explanation for a set of verified facts.  

Theory is a system of explanations that ties together a lot of facts.

Steps of the scientific method:  

1) ask a question about something that is observed.  

2) do background research.  

3) construct a hypothesis, an attempt to answer questions with an explanation that can be tested.  

4) test of hypothesis.  

5) analyze collected data and draw a conclusion.  

2) The answer is: D) hypothesis.

Hypothesis is a suggested explanation for an observable phenomenon.

Experimenters may test and reject several hypotheses before solving the problem.

A working hypothesis is provisionally accepted as a basis for further research.

A law in science is a generalized rule to explain a body of observations in the form of a verbal or mathematical statement.

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svetlana [45]

Answer:3844 cm^2

Explanation:

62 squared since it is a square, and area is base times height

3 0
3 years ago
Formic acid, which is a component of insect venom, has a ka = 1.8 ´ 10-4. what is the [h3o+] in a solution that is initially 0.1
scoray [572]
Answer is: concentratio of H₃O⁺ ions is 4.2·10⁻³ M.<span>
Chemical reaction: HCOOH(aq) + H</span>₂O(l) ⇄ HCOO⁻(aq) + H₃O⁺(aq).<span>
c(HCOOH) = 0,1 M.
[</span>H₃O⁺] = [HCOO⁻] = x.<span>
[HCOOH] = 0,1 M - x.
</span>Ka = [H₃O⁺] · [HCOO⁻] / [HCOOH].
0,00018 = x² / (0,1 M - x).<span>
Solve quadratic equation: x = </span>[H₃O⁺] = 0,0042 M.
7 0
3 years ago
A team of engineers has decided to design a new shoe for people suffering from a painful foot condition. Each of the following t
sp2606 [1]

Answer:

A. have subjects wear the shoes in an experimental trial to see if symptoms improve.

8 0
4 years ago
Read 2 more answers
Why sodium chloride is a poor conductor of electricity in solid state?​
aev [14]

Answer:

Because the electrons in this ionic compound arent free to move and so cannot carry charge. For an iconic compound to conduct electricity it must be a liquid, either in a molten form or dissolved in water.

Explanation:

Is this clear?

5 0
3 years ago
The cell potential of a redox reaction occurring in an electrochemical cell under any set of temperature and concentration condi
avanturin [10]

Answer : The actual cell potential of the cell is 0.47 V

Explanation:

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given redox reaction is :

Ni^{2+}(aq)+Zn(s)\rightarrow Ni(s)+Zn^{2+}(aq)

The balanced two-half reactions will be,

Oxidation half reaction : Zn\rightarrow Zn^{2+}+2e^-

Reduction half reaction : Ni^{2+}+2e^-\rightarrow Ni

The expression for reaction quotient will be :

Q=\frac{[Zn^{2+}]}{[Ni^{2+}]}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(0.0141)}{(0.00104)}=13.6

The value of the reaction quotient, Q, for the cell is, 13.6

Now we have to calculate the actual cell potential of the cell.

Using Nernst equation :

E_{cell}=E^o_{cell}-\frac{RT}{nF}\ln Q

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature = 316 K

n = number of electrons in oxidation-reduction reaction = 2 mole

E^o_{cell} = standard electrode potential of the cell = 0.51 V

E_{cell} = actual cell potential of the cell = ?

Q = reaction quotient = 13.6

Now put all the given values in the above equation, we get:

E_{cell}=0.51-\frac{(8.314)\times (316)}{2\times 96500}\ln (13.6)

E_{cell}=0.47V

Therefore, the actual cell potential of the cell is 0.47 V

4 0
3 years ago
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