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n200080 [17]
2 years ago
14

A compound is 48.6 % C, 8.2 % H, and 43.2 % O by mass. Calculate the empirical formula of this compound.

Chemistry
1 answer:
maria [59]2 years ago
6 0
Answer:
C2H3O
Explanation
:
C. H. O
48.6. 8.2. 43.2
r.a.m 12. 1. 16
no.of 48.4÷12. 8.2÷1. 43.2÷16
moles
4.05÷2.7. 8.2÷2.7. 2.7÷2.7
2. 3. 1
Therefore C2H3O
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Answer:

<h2>Dog's mitochondria lack the transport protein that transport  pyruvate ( end product of glycolysis) across the outer mitochondrial  membrane .</h2>

Explanation:

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2. The aerobic phases of cellular respiration in eukaryotes occur within  mitochondria. These aerobic phases are the TCA Cycle and the electron transport chain. Glycolysis occurs in the cytoplasm and the products of glycolysis enter into the mitochondria to continue cellular respiration.

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3 0
3 years ago
Energy is just like any other chemical or physical process, where it cannot be created or destroyed. Which Law states this fact?
Ganezh [65]

Answer:

Law of Conservation of Energy

Explanation:

5 0
4 years ago
How is ti possible that, when adding protons while moving left to right across a period, the size of an atom shrinks? Why is the
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4 0
3 years ago
Solid carbon (C) can burn in oxygen (O2). Select
babunello [35]

Answer:

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Explanation:

A reaction equation has <u>reactants on the left</u> and <u>products on the right</u>.

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You might see the equation both ways.

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C + O₂ in the products would mean no reaction has occurred. The problem can <u>solid carbon can burn in oxygen</u>, so a reaction will occur. For no reaction, you would put "NR" in the products.

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