Answer:
2.33g of iron (iii) chloride
50.0 mL of 5.00 M of sodium phosphate
FeCl3 + Na3PO4 > Fe(PO4) + 3NaCl
mol = conc × vol = 0.5 × 50/1000 = 0.025 mol Na3PO4
from the equation:
1 mol of Na3PO4 reacts with 1 mol FeCl3 = 3 mol of NaCl
0.025 mol = x
x = 0.0025 × 3 = 0.075 mol NaCl
mass = 0.075 g × 59 g/mol = 4.425 g NaCl
i guessed all of this so i dont know i it is correct
Evaporation,condensation,precipitation,sublimation,transpirtation,runoff and infiltration
Answer: 1.46moles
Explanation:
Applying PV= nRT
P= 1atm, V= 32.6L, R= 0.082, T = 273K
Substitute and simplify
1×32.6/(0.082×273)=n
n= 1.46moles
C: 12.0107 g/mol ≅ 12.00 g/mol
H: 1.00784 g/mol ≅ 1.008 g/mol
O: 15.999 g/mol ≅ 16.00 g/mol
n(molar mass of CH2O)= 180
n.30=180
n=6
molecular formula: c6h12o6 glucose
Answer:
friction
Explanation:
the resistance that one surface or object encounters when moving over another.
