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alexandr402 [8]

2 years ago

5

Debbie needs to fill juice cups for her little brother's birthday party. there are 20 juice cups and each juice cup holds 10 flu

id ounces. the juice comes in 1 gallon bottles. how many 1 gallon bottles of juice will Debbie need to purchase?
1
2
3
4

2 answers:

TEA [102]2 years ago

8 0

Debbie will need to purchase 2 gallon bottles of juice since there are 128 fluid ounces in one gallon.

maria [59]2 years ago

6 0

4 because 3 would only fill 9.8 per cup of the 20 cups so i guess it could be 3, but with 4 you get 12.8 per cup.

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kumpel [21]

The constant of proportionality is 4. Also, look at 36, and 9 because you could have just divided it it is not as complicated as you think.

5 0

2 years ago

Logan owed his brother $7.50. For his birthday, Logan received $20 from his grandpa. After paying his brother back, how much mon

evablogger [386]

Answer:

$12.50

Step-by-step explanation:

20 - 7.50=12.50

3 0

2 years ago

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Find the missing Side of the triangle

sammy [17]

Answer:

2√15

Step-by-step explanation:

Use the Pythagorean theorem.

2² + x² = 8²

x² + 4 = 64

x² = 60

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2 years ago

A standard number cube is tossed. Find the following probability. P(greater than 4 or odd)

lorasvet [3.4K]

A standard cube has 6 possible outcomes. But since we want to find P(4+ or odd), the outcomes become more narrow.
So:
6 outcomes -> 1, 2, 3, 4, 5, 6

But we want to find 4+
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4+ = 4, 5, 6

We also want to find all odd possibilities.
So:
odd = 1, 3, 5

As you can see, there is a 5 in both the 4+ and the odd numbers so 5 will only be counted once.
P(4+ or odd) = 1, 3, 4, 5, 6

So the probability of having an outcome that is P(4+ or odd) is:
5/6 or 0.8333 or 83.33%

Hope I helped!

8 0

2 years ago

Read 2 more answers

Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

b) $y(t) = y_{0}e^{-4t} + 2$ . It has a steady state.

Step-by-step explanation:

a) $y' -4y = -8$

The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

So

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

$-4C = -8$

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{4t} + 2$

b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

So

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

6 0

3 years ago