Question

For a flourish at the end of her act, a juggler tosses a single ball high in the air. She catches the ball 3.2 s later at the same height from which it was thrown. What was the initial upward speed of the ball?

Answer 1

Answer:

15.68 m/s

Explanation:

Given that,

She catches the ball 3.2 s later at the same height from which it was thrown.

When it reaches the maximum height, its height is equal to 0.

It will move under the action of gravity.

$t=\dfrac{2u}{g}$

2 here comes for the time of ascent and descent.

So,

$u=\dfrac{tg}{2}\\\\u=\dfrac{3.2\times 9.8}{2}\\\\u=15.68\ m/s$

So, the initial upward speed of the ball is 15.68 m/s.