Question

a red die is tossed then a green die is tossed. what is the probability that the red die shows a number larger than three and the green die shows a number less than three?

Answer 1

$|\Omega|=6\cdot6=36\\ |A|=3\cdot2=6\\\\ P(A)=\dfrac{6}{36}=\dfrac{1}{6}\approx17\%$