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Advocard [28]
3 years ago
8

Aneesha determined that the cost of attending her public four-year college in her first year will be $6,220. If the average cost

is expected to increase by 6%, what will be the cost of attending her second year in college?
$6,226.00

$6,257.32

$6,593.20

$6,820.00
Mathematics
2 answers:
almond37 [142]3 years ago
4 0
Since it increases by 6%, that means you times the amount by an EXTRA 6%. I.e. 6220 x 1.06 = $6593.20


grigory [225]3 years ago
3 0

Answer:

The answer is C)$6593.20

Step-by-step explanation:

6220 x 1.06 = $6593.20

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3 years ago
Solve the equation: k^2+5k+13=0
mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

x =  \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}  \\

From the question

a = 1 , b = 5 , c = 13

So we have

k =  \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)}  \\  =  \frac{ - 5 \pm \sqrt{25 - 52} }{2}  \\  =  \frac{ - 5 \pm \sqrt{ - 27} }{2}  \:  \:  \:  \:  \:  \:  \\  =  \frac{ - 5  \pm3 \sqrt{3}  \: i}{2}  \:  \:  \:  \:  \:  \:

<u>Separate the solutions</u>

k_1 =  \frac{ - 5 + 3 \sqrt{3} \: i }{2}  \:  \:  \:  \: or \\ k_2 =  \frac{ - 5 - 3 \sqrt{3}  \: i}{2}

The equation has complex roots

<u>Separate the real and imaginary parts</u>

We have the final answer as

k_1 =  -  \frac{5}{2}  +  \frac{3 \sqrt{3} }{2}  \: i \:  \:  \:  \: or \\ k_2 =  -  \frac{5}{2}  -  \frac{3 \sqrt{3} }{2}  \: i

Hope this helps you

8 0
3 years ago
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