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Drupady [299]
4 years ago
6

The volume of a weather balloon is 200.0 L and its internal pressure is 1.17 atm when it is launched at 20 °C. The balloon rises

to an altitude in the stratosphere where its internal pressure is 63 mmHg and the temperature is 210 K. What is the volume (in L) of the balloon then?
Chemistry
1 answer:
brilliants [131]4 years ago
8 0

Answer:

2022 L

Explanation:

Ideal gas laws will work for gas in the balloon

The general gas law is for a gas at two arbitrary states 1 and 2 is given by

(P₁ V₁)/T₁ = (P₂ V₂)/T₂

P₁ = 1.17 atm

V₁ = 200.0 L

T₁ = 20°C = 293.15 K

P₂ = 63 mmHg = 0.0829 atm

V₂ = ?

T₂ = 210 K

(1.17 × 200)/293.15 = (0.0829 × V₂)/210

V₂ = (210 × 1.17 × 200)/(293.15 × 0.0829)

V₂ = 2022 L

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Answer:

O2 is limiting reactant

Explanation:

To find the limiting reactant we need to convert the mass of each reactant to the moles using the formula weight. And, as 1 mole of C6H12O6 reacts with 6 moles of O2, we can know wich reactant will be over first (Limiting reactant) as follows:

<em>Moles C6H12O6:</em>

650g * (1mol/180.16g) = 3.608 moles C6H12O6

<em>Moles O2:</em>

650g * (1mol/32g) = 20.31 moles O2

Now, for a complete reaction of 3.608 moles of C6H12O6 are required:

3.608 moles C6H12O6 * (6mol O2 / 1mol C6H12O6) = 21.65 moles O2

As there are just 20.31 moles of O2,

<h3>O2 is limiting reactant</h3>
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Main job is to sort and package proteins and other substances in a plant cell
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Answer:

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<u>Answer:</u>

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