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kozerog [31]
3 years ago
5

which types of intermolecular forces are most likely to dominate between large molecules containing long chains of carbon atoms

bound to hydrogen atoms
Chemistry
1 answer:
Serga [27]3 years ago
6 0

Van der waals force

Explanation:

The intermoleclular forces are attraction between molecules. Interatomic forces are attraction between atoms in a compound.

In most hydrocarbons the weak Van der waals attraction are known.

  • These forces are weak attraction joining non-polar and polar molecules together.
  • These forces can also be found in layers of graphite.
  • They are of two types;

London dispersion forces are attraction that exists between non-polar molecules and the noble gas.

Dipole - Dipole attractions are forces of attraction existing in polar molecules.

In hydrocarbons, we have non-polar molecules and intermolecular attraction is london dispersion forces.

learn more:

Intermolecular forces brainly.com/question/10107765

#learnwithBrainly

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For a particular reaction at 235.8 °C, ΔG=−936.92 kJ/mol , and ΔS=513.79 J/(mol⋅K) . Calculate ΔG for this reaction at −9.9 °C.
Rudik [331]

Answer:

-138.9 kJ/mol

Explanation:

Step 1: Convert 235.8°C to the Kelvin scale

We will use the following expression.

K = °C + 273.15 = 235.8°C + 273.15 = 509.0 K

Step 2: Calculate the standard enthalpy of reaction (ΔH°)

We will use the following expression.

ΔG° = ΔH° - T.ΔS°

ΔH° = ΔG° / T.ΔS°

ΔH° = (-936.92kJ/mol) / 509.0K × 0.51379 kJ/mol.K

ΔH° = -3.583 kJ (for 1 mole of balanced reaction)

Step 3: Convert -9.9°C to the Kelvin scale

K = °C + 273.15 = -9.9°C + 273.15 = 263.3 K

Step 4: Calculate ΔG° at 263.3 K

ΔG° = ΔH° - T.ΔS°

ΔG° = -3.583 kJ/mol - 263.3 K × 0.51379 kJ/mol.K

ΔG° = -138.9 kJ/mol

8 0
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