Answer:
First, let's express pressure P in Pa and volume V in m3:
⇒P=175 kPa
⇒P=1.75×105 Pa
and
⇒V=275 ml
⇒V=2.75×10−4 m3
Then, let's solve the ideal gas law PV=nRT for temperature T:
⇒PV=nRT
⇒T=PVnR
Substituting the appropriate values into the equation:
⇒T=1.75×105×2.75×10−40.80×8.314 K
⇒T=48.1256.6512 K
∴T≈7.24 K
Therefore, the temperature is around 7.24 K.
Answer:
The starch test also known as the iodine test is used to test for the presence of starch.
Sorry if this isn’t detailed enough. You can go on google/wikipedia and find much more detail if necessary. ^-^
Answer:
528.25 Calories
Explanation:
From the question given above, the following data were obtained:
Energy in Joules = 2210.20 J
Energy in calories =?
We can convert 2210.20 J to calories by doing the following:
4.184 J = 1 cal
Therefore,
2210.20 J = 2210.20 J × 1 cal / 4.184 J
2210.20 J = 528.25 Calories
Thus, 2210.20 J is equivalent to 528.25 Calories.
Answer:
2NO + 4H-> N2 + 2 H2O
Explanation:
Both sides must be equal. :)
Answer:
Explanation:
Given that:
The heat of combustion of methylhydrazine =
It means that:
1 mole of methylhydrazine on combustion, releases of energy
Molar mass of methylhydrazine = 46.072 g/mol
Means that, 1 mole of methylhydrazine contains 46.072 g of methylhydrazine
Thus,
46.072 g of methylhydrazine on combustion, releases of energy
Also,
1 g of methylhydrazine on combustion, releases of energy
206.2 g of methylhydrazine on combustion, releases of energy
Heat released =