Answer:
i just had a test on this with 2 attempts and got it wrong on both but i do know that the answer is not...
the steepness of the models hillside
or
the rate of erosion on the hills
so the answer is either...
the amount of water sprayed on the hills
or
the type of material used to construct the model hills
but i think its the amount of water sprayed on the hills...i hope i helped a lil ;)
Explanation:
number 9 is : Organized Data is a customizable information product versioning and management system used to track and store document, images and other products or information
Answer:
The correct option is A
Explanation:
Some amino acids, called glucogenic amino acids, when catabolized convert there carbon backbones to tricarboxylic acid (TCA) cycle intermediates. These intermediates can be subsequently metabolized into carbon dioxide and water with the release of ATP or the formation of glucose (known as gluconeogenesis.
<u>All amino acids (with the exception of leucine and lysine) are glucogenic and can thus generate the carbon backbones required for gluconeogenesis</u>. Thus, the correct option is a.
Answer:
No
Explanation:
The given equation is not balanced
Chemical equation:
KClO₄ → KCl + O₂
Given Balanced chemical equation:
KClO₄ → 2KCl + 2O₂
Correctly balanced chemical equation:
2KClO₄ → 2KCl + 4O₂
Now this equation is correctly balanced.
There are two potassium atom two chlorine atoms and eight oxygen atoms on both side of equation. So this is correctly balanced.
Coefficient with reactant and product:
KClO₄ 2
KCl 2
O₂ 4
Answer:
See explanation below
Explanation:
This reaction is known as Ketone hydrolisis in acid medium. This involves the formation of an hemi cetal, and then, the acetal. This is often used to convert ketones or aldehydes in ethers.
The first step involves the reaction with the acid. The carbonile reacts with the acid and forms an alcohol there. The next step is the reaction of the alcohol, in this case, the methanol to form the hemi cetal. Then in the third step, we repeat the first step, using acid to turn the OH group into a great leaving group such water. Then the water leaves the molecule, leaving the space wide open in the next step for methanol, and the acetal is formed.
See picture for the curved arrow mechanism
