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3 years ago

Which of the following have the most similar properties?

Chemistry

1 answer:

rjkz [21]3 years ago

6 0

Answer:

Option-B (Carbon and Silicon)

Explanation:

Among the given pairs only carbon and silicon have the most similar properties. This is because,

Sodium and Magnesium belong to different groups. Sodium present in Group I has one electron in its valence shell and capable of transferring only one electron while, Magnesium present in Group II have two electrons in its valence shell and is capable of donating two electrons. Hence, both show different properties.

Example:

2 Na + Cl₂ → NaCl

Mg + Cl₂ → MgCl₂

As shown in reactions when Sodium and Magnesium are treated with Cl₂ they give a products with different proportions.

Carbon and Silicon show almost same properties because both belong to Group IV hence both are capable of forming four bonds. Also, they share the same property of self linkage in making a long chains.

Argon and Chlorine also belong to two different groups. Argon is present in Group VIII (Noble Gases) and Chlorine is present in Group VII (Halogens). Hence, Argon is an inert specie which is non reactive while Chlorine gives different reaction easily.

Potassium and Calcium belong to different groups. Potassium present in Group I has one electron in its valence shell and capable of transferring only one electron while, Calcium present in Group II have two electrons in its valence shell and is capable of donating two electrons. Hence, both show different properties.

Example:

2 K + Cl₂ → KCl

Ca + Cl₂ → CaCl₂

As shown in reactions when Potassium and Calcium are treated with Cl₂ they give a products with different proportions.

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Given: logK=nE∘0.0592 What is the value K for this redox reaction? Zn2+(aq) + 2 Cl−(aq) → Zn(s) + Cl2(

anygoal [31]

K = 2.4 × 10^(-72)

Step 1. Determine the value of n

Zn^(2+) + 2e^(-) → Zn

2Cl^(-) → Cl_2 + 2e^(-)

Zn^(2+) + 2Cl^(-) → Zn + Cl_2

∴ n = 2

Step 2. Calculate K

logK = nE°/0.0592 V = [2 × (-2.12 V)]/0.0592 V = -71.62

K = 10^(-71.62) = 2.4 × 10^(-72)

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3 years ago

Given the following balanced reaction between nitrogen gas and oxygen gas to produce nitrous oxide gas, how many moles of nitrou

den301095 [7]

Answer is: 3,3 mol of nitrous oxide gas is produced in this chemical reaction.
Chemical reaction: N₂ + O₂ → 2NO.
n(N₂) = 1,65 mol.
n(NO) = ?
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n - amount of substance.

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4 years ago

Question 8

nexus9112 [7]

72 degrees C (minus 273)

6 0

3 years ago

Consider the reaction: NO2(g) + CO(g) ⇌ NO(g) + CO2(g) Kc = 0.30 at some temperature. If the initial mixture has the concentrati

Stolb23 [73]

This is an incomplete question, here is a complete question.

Consider the reaction: $NO_2(g)+CO(g)\rightleftharpoons NO(g)+CO_2(g)$

Kc = 0.30 at some temperature.

If the initial mixture has the concentrations below, the system is_______.

Chemicals Concentration (mol/L)

- NO₂ 0.024

- CO 0.360

- NO 0.180

- CO₂ 0.120

Possible answers:

1) not at equilibrium and will remain in an unequilibrated state.

2) not at equilibrium and will shift to the left to achieve an equilibrium state.

3) not at equilibrium and will shift to the right to achieve an equilibrium state.

4) at equilibrium

Answer : The correct option is, (2) not at equilibrium and will shift to the left to achieve an equilibrium state.

Explanation:

Reaction quotient (Qc) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

First we have to determine the value of reaction quotient (Qc).

The given balanced chemical reaction is,

$NO_2(g)+CO(g)\rightleftharpoons NO(g)+CO_2(g)$

The expression for reaction quotient will be :

$Q_c=\frac{[NO][CO_2]}{[NO_2][CO]}$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

$Q_c=\frac{(0.180)\times (0.120)}{(0.024)\times (0.360)}=2.5$

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

There are 3 conditions:

When $Q>K$ that means product > reactant. So, the reaction is reactant favored.

When $Q$ that means reactant > product. So, the reaction is product favored.

When $Q=K$ that means product = reactant. So, the reaction is in equilibrium.

The given equilibrium constant value is, $K_c=0.30$

From the above we conclude that, the $Q>K$ that means reactant < product. So, the reaction is reactant favored that means reaction must shift to the reactant or left to be in equilibrium.

Hence, the correct option is, (2) not at equilibrium and will shift to the left to achieve an equilibrium state.

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3 years ago

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Rom4ik [11]

Answer:

Explanation:

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