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PSYCHO15rus [73]
3 years ago
10

Which of the following have the most similar properties?

Chemistry
1 answer:
rjkz [21]3 years ago
6 0

Answer:

             Option-B (Carbon and Silicon)

Explanation:

                  Among the given pairs only carbon and silicon have the most similar properties. This is because,

Sodium and Magnesium belong to different groups. Sodium present in Group I has one electron in its valence shell and capable of transferring only one electron while, Magnesium present in Group II have two electrons in its valence shell and is capable of donating two electrons. Hence, both show different properties.

Example:

                                           2 Na  +  Cl₂    →     NaCl

                                           Mg  +  Cl₂    →    MgCl₂

As shown in reactions when Sodium and Magnesium are treated with Cl₂ they give a products with different proportions.

Carbon and Silicon show almost same properties because both belong to Group IV hence both are capable of forming four bonds. Also, they share the same property of self linkage in making a long chains.

Argon and Chlorine also belong to two different groups. Argon is present in Group VIII (Noble Gases) and Chlorine is present in Group VII (Halogens). Hence, Argon is an inert specie which is non reactive while Chlorine gives different reaction easily.

Potassium and Calcium belong to different groups. Potassium present in Group I has one electron in its valence shell and capable of transferring only one electron while, Calcium present in Group II have two electrons in its valence shell and is capable of donating two electrons. Hence, both show different properties.

Example:

                                           2 K  +  Cl₂    →     KCl

                                           Ca  +  Cl₂    →    CaCl₂

As shown in reactions when Potassium and Calcium are treated with Cl₂ they give a products with different proportions.

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Which ion does not have a noble gas configuration in its ground state? which ion does not have a noble gas configuration in its
Luda [366]

Answer: Option (d) is the correct answer.

Explanation:

The atomic number of Al is 13, so the electronic configuration of Al is as follows.

            1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}

         = [Ne]3s^{2}3p^{1}

Al^{3+} = [Ne]

The atomic number of Sc is 21, so the electronic configuration of Sc is as follows.

         1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{1}

        = [Ar]4s^{2}3d^{1}

 Sc^{3+} = [Ar]

The atomic number of As is 33, so the electronic configuration of As is as follows.

         1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{3}

         = [Ar]4s^{2}3d^{10}4p^{3}

 As^{3-} = [Ar]4s^{2}3d^{10}4p^{6} = [Kr]

The atomic number of Ga is 31, so the electronic configuration of Ga is as follows.

        1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{1}

       = [Ar]4s^{2}3d^{10}4p^{1}

 Ga^{3+} = [Ar]3d^{10}

Therefore, we can conclude that galium (Ga) ion does not have a noble gas configuration in its ground state.

4 0
2 years ago
Read 2 more answers
Water can be a solid
Degger [83]

Explanation:

Transpiration: This is the evaporation of liquid water from plants and trees into the Earth's atmosphere. Nearly all water that enters the roots transpires into the atmosphere. Sublimation: This is the process where ice and snow (a solid) changes into a gas without moving through the liquid phase

3 0
3 years ago
Read 2 more answers
The Ostwald process for the commercial production of nitric acid from ammonia and oxygen involves the following steps:
bagirrra123 [75]

Answer:

12 NH_3 (g)+ 21 O_2 (g) + \longrightarrow  14 H_2O (l) + 8 HNO_3 (g) + 4 NO (g)

Explanation:

The steps of the Ostwald process:

4 NH_3 (g) + 5 O_2 (g) \longrightarrow 4 NO (g) + 6 H_2O (g)

2 NO (g) + O_2 (g) \longrightarrow 2 NO_2 (g)

3 NO_2 (g) + H_2O (l) \longrightarrow 2 HNO_3 (g) + NO (g)

Combinning the equations:

4 NH_3 (g) + 5 O_2 (g) \longrightarrow 4 NO (g) + 6 H_2O (g)

+

(2 NO (g) + O_2 (g) \longrightarrow 2 NO_2 (g))*2

+

(3 NO_2 (g) + H_2O (l) \longrightarrow 2 HNO_3 (g) + NO (g))*4/3

=

4 NH_3 (g)+ 4 NO (g)+ 7 O_2 (g) + 4 NO_2 (g) +4/3 H_2O (l) \longrightarrow 4 NO (g) + 6 H_2O (g) +  4 NO_2(g) + 8/3 HNO_3 (g) + 4/3 NO (g)

Simplifying:

4 NH_3 (g)+ 7 O_2 (g) + \longrightarrow  14/3 H_2O (l) + 8/3 HNO_3 (g) + 4/3 NO (g)

12 NH_3 (g)+ 21 O_2 (g) + \longrightarrow  14 H_2O (l) + 8 HNO_3 (g) + 4 NO (g)

The overall reaction is endothermic becuase the formation of new chemical bonds requires energy consumption.

4 0
3 years ago
4. If an experimental value for a given observation was 415 nm while the theoretical value
Alex

Answer: % error of observation is 4.77%

Explanation:

Given:

Observation value = 415nm

theoretical value= 435.8nm

Percent error of observation = theoretical value- observation value/ theoretical value x 100 %

= 435.8-415/435.8= 0.04772 x 100 = 4.77%

therefore % error of observation is 4.77%

7 0
3 years ago
Hydrogen gas, iodine vapor, hydrogen iodine are mixed in a flask and heated to 696°C. H2(g) + I2(g) ⇋ 2 HI(g) Kc = 52 at 696°C I
Anettt [7]

Answer: The equilibrium concentration of hydrogen gas is 0.0269 M

Explanation:

The chemical reaction follows the equation:

                  H_2(g)+I_2(g)\rightleftharpoons 2HI(g)

At t = 0          0.044M     0.044M              0.177M  

At t=t_{eq}    (0.044-x)M    (0.044-x)M      (0.177+x)M

The expression for K_c for the given reaction follows:

K_c=\frac{[HI]^2}{[H_2]\times [I_2]}

We are given:

K_c=52

Putting values in above equation, we get:

52=\frac{(0.177+x)^2}{(0.044-x)^2}

x=0.0171M

Hence, the equilibrium concentration of hydrogen gas is (0.044-x) M =(0.044-0.0171) M= 0.0269 M

7 0
2 years ago
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