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Grace [21]
3 years ago
15

In order to prepare a 0.523 m aqueous solution of potassium iodide, how many grams of potassium iodide must be added to 2.00kg o

f water?
Chemistry
1 answer:
Lerok [7]3 years ago
6 0
M = amount of the solute  / mass of the <span>solvent

0.523 = x / 2.00 

x = 0.523 * 2.00

x = 1,046  moles

molar mass KI = </span><span>166.0028 g/mol
</span><span>
Mass = 1,046 * 166.0028

Mass </span>≈<span> 173.63 g

hope this helps!

</span>
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Calcium must lose two electrons to get a full outer shell. what is the name of the group to which calcium belongs
11111nata11111 [884]
The answer to this question would be: alkaline earth metal

Alkali earth metal is the second column group of the periodic table. In this group, the element has 2 extra electrons in their outer cells. That is why most of this metal has 2+ charge.
Their neighbor is the alkali metal which was the first column of the periodic table. The name is similar so don't confused and mix them each other.
4 0
4 years ago
a 2.7 L of N2 is collected at 121kpa and 288 K . if the pressure increases to 202 kpa and the temperature rises to 303 K , what
jok3333 [9.3K]

Answer:

The gas will occupy a volume of 1.702 liters.

Explanation:

Let suppose that the gas behaves ideally. The equation of state for ideal gas is:

P\cdot V = n\cdot R_{u}\cdot T (1)

Where:

P - Pressure, measured in kilopascals.

V - Volume, measured in liters.

n - Molar quantity, measured in moles.

T - Temperature, measured in Kelvin.

R_{u} - Ideal gas constant, measured in kilopascal-liters per mole-Kelvin.

We can simplify the equation by constructing the following relationship:

\frac{P_{1}\cdot V_{1}}{T_{1}} = \frac{P_{2}\cdot V_{2}}{T_{2}} (2)

Where:

P_{1}, P_{2} - Initial and final pressure, measured in kilopascals.

V_{1}, V_{2} - Initial and final volume, measured in liters.

T_{1}, T_{2} - Initial and final temperature, measured in Kelvin.

If we know that P_{1} = 121\,kPa, P_{2} = 202\,kPa, V_{1} = 2.7\,L, T_{1} = 288\,K and T_{2} = 303\,K, the final volume of the gas is:

V_{2} = \left(\frac{T_{2}}{T_{1}} \right)\cdot \left(\frac{P_{1}}{P_{2}} \right)\cdot V_{1}

V_{2} = 1.702\,L

The gas will occupy a volume of 1.702 liters.

6 0
3 years ago
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Leona [35]

Answer:

weak bonds break and strong bonds form

Explanation:

An exothermic reaction is a chemical reaction in which heat energy is evolved during the reaction process.

Bond formation requires energy while bond breakage releases energy. More energy is needed for the formation of weak bonds as compared to strong bonds.

<em>Hence, when weak bonds break, they release more energy than needed to make a corresponding strong bond leading to the release of the remaining energy as heat.</em>

6 0
3 years ago
How many moles of al does 13.49 g of al represent?
Harlamova29_29 [7]
Use equation
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7 0
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Gases are easily compressible

8 0
4 years ago
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