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kupik [55]
3 years ago
12

A spring gun is made by compressing a spring in a tube and then latching the spring at the compressed position. A 4.87-g pellet

is placed against the compressed and latched spring. The spring latches at a compression of [04]____________________ cm, and it takes a force of 9.13 N to compress the spring to that point. How much work (J) is done by the spring when the latch is released and the pellet leaves the tube?

Physics
1 answer:
Serga [27]3 years ago
8 0

Complete Question

The complete question is shown on the first uploaded image

Answer:

The work done by the spring is = 0.27 J

Explanation:

Force = torque × length

Given

F = 9.13 N

length (L) = 5.91 cm  = 0.0591 m                         [Note 1 m = 100 cm ]

considering the formula above

          9.13 = k * 0.0591    where k denotes torque

          k = 154.48\ N/m

Energy Stored  = \frac{1}{2} k x^2

                          = \frac{1}{2} * 154.48 * (0.0591)^2

                         = 0.27J  

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