A spring gun is made by compressing a spring in a tube and then latching the spring at the compressed position. A 4.87-g pellet
is placed against the compressed and latched spring. The spring latches at a compression of [04]____________________ cm, and it takes a force of 9.13 N to compress the spring to that point. How much work (J) is done by the spring when the latch is released and the pellet leaves the tube?
1 answer:
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The time when the two players will collide is 0.96 s.
The equation of motion of the two players is given as;
x1 = 0.1 m + (–3.9 m/s )t
x2 = –6.3 m + (2.8 m/s )t
The time when the two players collide, their displacement is equal or the difference in their position will be zero.
Thus, the time when the two players will collide is 0.96 s.
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Answer:
0.037 N/m
Explanation:
The web acts as a spring, so it obeys Hook's law:
(1)
where
F is the force exerted on the web
k is the spring constant
x is the stretching/compression of the web
In this problem, we have:
- The mass of the fly is
- The force exerted on the web is the weight of the fly, so:
- The stretching of the web is
So if we solve eq.(1) for k, we find the spring constant: