The current in the junction is 1350 mA or 1.350 A.
Explanation:
As per Kirchoff's first law, the algebraic sum of current meeting at any junction should be equal to the algebraic sum of current leaving the junction. As in the present case, three parallel branch circuit is given the current in 250 mA, 300 mA and 800 mA, respectively, the sum of these three current will be equal to the current in the junction.
So,
I₁+I₂+I₃ = I₄
So I₁,I₂ and I₃ are the current passed in the three parallel branches and I₄ is the current in the junction.
250 + 300 + 800 = 1350 mA
So the current in the junction is 1350 mA or 1.350 A.
The radius of the circle, in cm, after t seconds would be 50t
The area, A, of the circle after t seconds is expressed in the equation: A = pi * r^2
A = pi * (50T)^2 = pi*2500*t^2
The change of area per unit time is obtained by differentiating the equation
A' = pi*2500*2*t A' = pi*5000*t
when t = 3 secondsA' = pi*5000*3 = 47122 cm2/s
Answer:
b) 7.00
Explanation:
N( t ) = -20( t - 5 )²
dN/ dt = -20 x 2 ( t - 5 )
For maximum N ( depth )
dN/dt = 0
- 40 ( t - 5 ) = 0
t = 5
So at 2 + 5 = 7 .00 am depth of water reaches its maximum.
The correct answer is option B, representational
All the painters in Peale family were involved in paintings which represent the day today life activities or were portraits or mimic some natural forms.
Charles Willson Peale , the head of the Peale family was known for painting sixty portraits of the first American president, George Washington. He also painted portraits of portraits of notable people of the society such as Benjamin Franklin, Thomas Jefferson etc.
Most of the paintings of peale family were based on the theme of family, art and science. Six of Peale’s son were known for their renaissance paintings. His oldest son Raphelle was known for still life paintings.
Titian Ramsay Peale, Charles’ youngest son was a naturalist painter.
Answer:
165 degrees F (high)
Explanation:
to destroy the most heat pathogens found in raw poultry
