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klemol [59]
3 years ago
10

. 2. El calor específico de un líquido es de 4186 j/kg.K. Su masa es de 100g. ¿Qué cantidad de calor hay

Physics
1 answer:
mote1985 [20]3 years ago
4 0

Answer:

Calor absorbido, Q = 5023.2 Joules

Explanation:

Dados los siguientes datos;

Masa = 100g to kg = 100/1000 = 0.1kg

Temperatura inicial, T1 = 293.15 K

Temperatura final, T2 = 305.15K

Capacidad calorífica específica = 4186 j/kg.K.

Para encontrar la cantidad de calor necesaria;

La capacidad calorífica viene dada por la fórmula;

Q = mct

Dónde;

Q representa la capacidad calorífica o la cantidad de calor.

m representa la masa de un objeto.

c representa la capacidad calorífica específica del agua.

dt representa el cambio de temperatura.

dt = T2 - T1

dt = 305.15 - 293.15

dt = 12 K

Sustituyendo en la fórmula, tenemos;

Q = 0.1*4186*12

Q = 5023.2

Calor absorbido, Q = 5023.2 Joules

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A cake is removed from a 350◦F oven and placed on a cooling rack in a 70◦F room. After 30 minutes the cake is 200◦F. When will i
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Answer:

350 F to 100 F it take approx 87.33 min  

Explanation:

given data

oven = 350◦F

cooling rack = 70◦F

time = 30 min

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solution

we apply here Newtons law of cooling  

\frac{dT}{dt} = -k(T-Ta)

\frac{dy}{dt} = \frac{d}{dt} (T(t) -Ta)

= \frac{dT}{dt} -\frac{dTa}{dt} =\frac{dT}{dt} = -k(T-Ta)

-ky \frac{dy}{dt} = -ky

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so here

200 = 70 + ( 350 - 70 ) e^{-k30}

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