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nasty-shy [4]
3 years ago
8

As you sit on a dock, you notice a wave crest pass. You count another 10

Chemistry
1 answer:
denpristay [2]3 years ago
6 0

Answer:

Frequency of the waves = 0.667 Hz

Explanation:

Given:

Number of waves = 10

Time taken = 15 seconds

Find:

Frequency of the waves.

Computation:

⇒ Frequency of the waves = Number of waves / Time taken

⇒ Frequency of the waves = 10 / 15

⇒ Frequency of the waves = 0.667 Hz

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A chemist fills a reaction vessel with 0.750 M lead (II) (Pb2+) aqueous solution, 0.232 M bromide (Br) aqueous solution, and 0.9
Ronch [10]

Answer:

The free energy = -20.46 KJ

Explanation:

given Data:

Pb²⁺ = 0.750 M

Br⁻ = 0.232 M

R = 8.314 Jk⁻¹mol⁻¹

T = 298K

The Gibb's free energy is calculated using the formula;

ΔG = ΔG° + RTlnQ -------------------------1

Where;

ΔG° = standard Gibb's freeenergy

R = Gas constant

Q = reaction quotient

T = temperature

The chemical reaction is given as;

Pb²⁺(aq) + 2Br⁻(aq) ⇄PbBr₂(s)

The ΔG°f are given as:

ΔG°f (PbBr₂)  = -260.75 kj.mol⁻¹

ΔG°f (Pb²⁺)   = -24.4 kj.mol⁻¹

ΔG°f (2Br⁻)    = -103.97 kj.mol⁻¹

Calculating the standard gibb's free energy using the formula;

ΔG° = ξnpΔG°(product) - ξnrΔG°(reactant)

Substituting, we have;

ΔG° =[1mol*ΔG°f (PbBr₂)] - [1 mol *ΔG°f (Pb²⁺) +2mol *ΔG°f (2Br⁻)]

ΔG° =(1 *-260.75 kj.mol⁻¹) - (1* -24.4 kj.mol⁻¹) +(2*-103.97 kj.mol⁻¹)

      = -260.75 + 232.34

     = -28.41 kj

Calculating the reaction quotient Q using the formula;

Q = 1/[Pb²⁺ *(Br⁻)²]

   = 1/(0.750 * 0.232²)

  = 24.77

Substituting all the calculated values into equation 1, we have

ΔG = ΔG° + RTlnQ

ΔG = -28.41 + (8.414*10⁻³ * 298 * In 24.77)

     = -28.41 +7.95

    = -20. 46 kJ

Therefore, the free energy of reaction = -20.46 kJ

8 0
3 years ago
33) 1 e = ........С <br>O 1.6*10^-27 <br>O * 1.6 *10^-19 <br>O 1.66 * 10^-19 <br>o 1.66* 10^-27​
Brilliant_brown [7]

Answer

0.16574

Explanation:

because why not

8 0
2 years ago
Problem: What is the kinetic energy of a 0.500 kg rabbit, running at 8.00 m/s? Calculate using the formula,
arsen [322]

Answer:

the answer s 9.000ms

Explanation:

that's the answer

4 0
3 years ago
To determine the concentration of an EDTA solution, 4.11 g of Zn metal was used. The volume of EDTA solution needed to reach the
USPshnik [31]

Answer:

2.23M

Explanation:

Molarity of a solution is calculated thus

Molarity = number of moles (n) ÷ volume (V)

According to this question, 4.11g of Zn metal was used in order to reach a volume of EDTA solution of 28.26 mL.

28.26mL = 28.26/1000

= 0.02826L

Using mole = mass/molar mass to calculate no. of moles of Zn

Mole = 4.11/65.4

mole = 0.0628mol

Molarity = 0.0628 ÷ 0.02826

Molarity = 2.23M

The concentration of the EDTA solution used is 2.23M

7 0
3 years ago
Which of the following statements about the relationship between science and technology is not true
Dafna11 [192]
Because they r the same

8 0
3 years ago
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