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3 years ago

PLZ HELP! I WILL GIVE BRAINLIEST OR WHATEVER U PPL WANT JUST HELP!

1 answer:

5 0

Newton's first law is sometimes known as the law of inertia. It is the law that states that an object at rest will stay at rest and an object in motion will stay in motion unless a force acts upon it. For example, if I was working with a wrench in space an it slipped, it would keep on going in one direction with a constant speed unless it hits something. Hope this helps!

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State the Newton's law Newton's second law of motion

ra1l [238]

Answer:

It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.

6 0

2 years ago

A gas, behaving ideally, fills a fixed volume container at a pressure P₁ and at a temperature T₁. The temperature of the contain

Lynna [10]

Answer:

c. P₁/T₁=P₂/T₂

Explanation:

neither Avogadro’s, Charles’, or Boyle’s law formula can be used, since some parameters like volume is not given,

to find P₂, given P₁, T₁, and T₂ we will therefore use Gay-lussac's law.

gay lussacs law state that, provided volume is kept constant, pressure is directly proportional to temperature.

the volume volume is said to be filled, i.e its is kept constants when temperature is change

4 0

3 years ago

Objects with masses of 135 kg and a 435 kg are separated by 0.500 m. Find the net gravitational force exerted by these objects o

IrinaVladis [17]

Answer:

The net gravitational force on the mass is $1.27\times 10^{-5}$

Explanation:

We have by Newton's law of gravity the force of attraction between masses $m_{1},m_{2}$

$F_{att}=G\frac{m_{1}m_{2}}{r^{2}}$

Applying vales we get

Force of attraction between 135 kg mass and 38 kg mass is

$F_{1}=6.67\times 10^{-11}\frac{135\times 38}{(0.25)^{2}}\\\\F_{1}=5.47\times 10^{-6}N$

Force of attraction between 435 kg mass and 38 kg mass is

$F_{2}=6.67\times 10^{-11}\frac{435\times 38}{(0.25)^{2}}\\\\F_{2}=1.76\times 10^{-5}N$

Thus the net force on mass 38.0 kg is $F_{2}-F_{1}=1.76\times 10^{-5}-5.47\times 10^{-6}\\\\F_{2}-F_{1}=1.27\times 10^{-5}$

8 0

3 years ago

A space craft is moving relative to the earth , an observer on the earth finds that, between 1pm and 2pm according to her clock,

madam [21]

The speed of the space craft relative to the earth is given as: 0.024c. This is solved using the the equation for time dilation.

<h3>What is time dilation?</h3>

Time dilation is the "slowing down" of a clock as determined by an observer in relative motion with regard to that clock under the theory of special relativity.

The formula is given as :

Δt = [Δr]/ √ 1 - (v²/c²)

Thus,

v = c√1 - (Δr/Δt)²

= c √(1 - (3600/3601)²

v = 0.024c

Learn more about time dilation at:
brainly.com/question/1933572
#SPJ1

4 0

2 years ago

An alpha particle(the nucleus of a helium atom) has a mass of 6.64*10^-27kg and a charge of +2e. What are the magnitude and dire

emmasim [6.3K]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Weight = electric force
<span>mg = qE </span>

<span>6.64x10^-27 x 9.81 = (2 x 1.60x10^-19) E
</span>qE =mg,
<span>E = mg/q = 6.64•10^-27•9.8/2•1.6•10^-19 =2.03•10^-7 V/m</span>

8 0

3 years ago

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