The pH of a solution is 9.02.
c(HCN) = 1.25 M; concentration of the cyanide acid
n(NaCN) = 1.37 mol; amount of the salt
V = 1.699 l; volume of the solution
c(NaCN) = 1.37 mol ÷ 1.699 l
c(NaCN) = 0.806 M; concentration of the salt
Ka = 6.2 × 10⁻¹⁰; acid constant
pKa = -logKa
pKa = - log (6.2 × 10⁻¹⁰)
pKa = 9.21
Henderson–Hasselbalch equation for the buffer solution:
pH = pKa + log(cs/ck)
pH = pKa + log(cs/ck)
pH = 9.21 + log (0.806M/1.25M)
pH = 9.21 - 0.19
pH = 9.02; potential of hydrogen
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NI(s)->NI^2+(aq)+2e^-(oxidation)
Answer:
D. the sea of electrons
Explanation:
Metallic bonds are defined as the bonds formed between two or more metals. Silver atom form metallic bond with other silver atoms.
In metallic bond, the free electrons or valence electrons present in s and p orbitals delocalize. The valence electrons do not move around the atoms or enter the atoms whereas they form a sea of electrons in which they surround the nuclei (positively charged) of the metal ions interacting. The valence electrons are then freely move in the space between the atomic nuclei.
Hence, the correct answer is "D. the sea of electrons".