All categories

3 years ago

I2 + Ti+4 ----> Ti + IO3- reducing agent

Chemistry

1 answer:

Schach [20]3 years ago

3 0

In order to identify the reducing agent let us check the oxidation states

I2 + Ti+4 ----> Ti + IO3- reducing agent

I2 : oxidation state of I = 0

Ti^+4 = oxidation state of Ti = +4

Ti : oxidation state = 0

IO3^-1 , oxidation state of Iodine = +5

So here the Ti undergoes reduction hence it is oxidizing agent

Where iodine undergoes oxidation hence it is reducing agent

You might be interested in

The tabulated data were collected for this reaction:

erastovalidia [21]

Answer:

ai) Rate law, $Rate = k [CH_3 Cl] [Cl_2]^{0.5}$

aii) Rate constant, k = 1.25

b) Overall order of reaction = 1.5

Explanation:

Equation of Reaction:

$CH_{3} Cl (g) + 3 Cl_2 (g) \rightarrow CCl_4 (g) + 3 HCl (g)$

If $A + B \rightarrow C + D$ , the rate of backward reaction is given by:

$Rate = k [A]^{a} [B]^{b}\\k = \frac{Rate}{ [A]^{a} [B]^{b}}\\k = \frac{Rate}{ [CH_3 Cl]^{a} [Cl_2]^{b}}$

k is constant for all the stages

Using the information provided in lines 1 and 2 of the table:

$0.014 / [0.05]^a [0.05]^b = 00.029/ [0.100]^a [0.05]^b\\0.014 / [0.05]^a [0.05]^b = 00.029/ [2*0.05]^a [0.05]^b\\0.014 / = 0.029/ 2^a\\2^a = 2.07\\a = 1$

Using the information provided in lines 3 and 4 of the table and insering the value of a:

$0.041 / [0.100]^a [0.100]^b = 0.115 / [0.200]^a [0.200]^b\\0.041 / [0.100]^a [0.100]^b = 0.115 / [2 * 0.100]^a [2 * 0.100]^b\\$

$0.041 = 0.115 / [2 ]^a [2]^b\\ \[[2 ]^a [2]^b = 0.115/0.041\\ \[[2 ]^a [2]^b = 2.80\\\[[2 ]^1 [2]^b = 2.80\\\[[2]^b = 1.40\\b = \frac{ln 1.4}{ln 2} \\b = 0.5$

The rate law is: $Rate = k [CH_3 Cl] [Cl_2]^{0.5}$

The rate constant $k = \frac{Rate}{ [CH_3 Cl]^{a} [Cl_2]^{b}}$ then becomes:

$k = 0.014 / ( [0.050] [0.050]^(0.5) )\\k = 1.25$

b) Overall order of reaction = a + b

Overall order of reaction = 1 + 0.5

Overall order of reaction = 1.5

3 0

3 years ago

Explain the three laws of chemical reaction in detain gilling examples

kotykmax [81]

Answer:

The three laws of Chemical Reaction are .The law of constant proportions. The law of multiple proportions. The law of reciprocal proportions.

A chemical compound is always found to be made up of the same elements combined together in the same fixed proportion by mass.

potassium and chlorine gas ---> chloride.

Hope this helps, have a good day.✌

8 0

2 years ago

Calculate the molarity of a solution made by dissolving 4.0 g of calcium bromide, CaBr2, in enough water to give 200 mL of solut

Troyanec [42]

Answer:

0.1 M

Explanation:

Molarity = number of moles / litres of solution.

4 g of calcium bromide = 0.02 mol

(found by dividing 4 g by the atomic mass of CaBr2, which is 199.886)

200 mL of solution = 0.2 litres

Molarity = 0.02 mol / 0.2 L = 0.1 M

8 0

2 years ago

Is kingdom more specific taxon than family?

Eva8 [605]

Yes the kingdom is more specific

5 0

3 years ago

What are chemical formulaes?<br> give your own response!!

lbvjy [14]

Answer:

is a way of presenting information about the chemical proportions of atoms

Explanation:

8 0

2 years ago