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stich3 [128]
3 years ago
9

8. Which type of bond results when one or more valence

Chemistry
1 answer:
Gekata [30.6K]3 years ago
8 0

Answer:

B

Explanation:

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DUEEEEE IN 1 minutess!!! BEING TIMED!!
melomori [17]

Answer:

pH = 13

The higher the pH, the more basic.

Good luck :)

6 0
3 years ago
If the fugacity of a pure component at the conditions of an ideal solution is 40 bar and its mole fraction is 0.4, what is its f
yaroslaw [1]

Answer : The fugacity in the solution is, 16 bar.

Explanation : Given,

Fugacity of a pure component = 40 bar

Mole fraction of component  = 0.4

Lewis-Randall rule : It states that in an ideal solution, the fugacity of a component is directly proportional to the mole fraction of the component in the solution.

Now we have to calculate the fugacity in the solution.

Formula used :

f_i=X_i\times f_i^o

where,

f_i = fugacity in the solution

f_i^o = fugacity of a pure component

X_1 = mole fraction of component

Now put all the give values in the above formula, we get:

f_i=0.4\times 40\text{ bar}

f_i=16\text{ bar}

Therefore, the fugacity in the solution is, 16 bar.

4 0
3 years ago
HELP Me Please I will give 20 points
lisabon 2012 [21]

Answer:

1c

2a

3b

Explanation:

5 0
3 years ago
Read 2 more answers
What is the volume of 500g of CO2?
Airida [17]

Weighs 0.001836 gram per cubic centimeter or 1.836 kilogram per cubic meter


Try to see if this helps

3 0
3 years ago
Read 2 more answers
For the reaction: N2O5(g) \longrightarrow⟶ 2NO2(g) + 1/2O2(g)
ivanzaharov [21]
The given equation from the problem above is already balance,
                                 N2O5 ---> 2NO2 + 0.5O2
Since, in every mole of N2O5 consumed, 2 moles of NO2 are formed, we can answer the problem by multiplying the given rate, 7.81 mol/L.s with the ratio.
                    (7.81 mol/L.s) x (2 moles NO2 formed/ 1 mole of N2O5 consumed)
                       = 15.62 mol/L.s
The answer is the rate of formation of NO2 is approximately 15.62 mol/L.s. 
5 0
3 years ago
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