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2 years ago

8

A weight suspended from a spring is seen to bob up and down over a total distance of 20 centimeters twice each second.

1 answer:

Zielflug [23.3K]2 years ago

5 0

<u>Answer</u>

8. 2 Hz

9. 0.5 seconds

10. 20 cm

<u>Explanation</u>

<u>Q 8</u>

Frequency is the number of oscillation in a unit time. It is the rate at which something repeats itself in a second.

In this case, the spring bob up and down 2 times per second.

∴ Frequency = 2 Hz

<u>Q 9</u>

Period is the time taken to complete one oscillation.

2 oscillations takes 1 second

1 oscillation = 1/2 seconds.

∴ Period = 0.5 seconds

<u>Q 10</u>

Amplitude is the the maximum displacement of the spring.

In this case the spring bob up 20 cm. This is it's displacement.

∴ Amplitude = 20 cm

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Here in all such collision type question we can use momentum conservation as we can see that there is no external force on this system

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3 years ago

Ships A and B leave port together. For the next two hours, ship A travels at 40.0 mph in a direction 35.0° west of north while t

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Answer:

Explanation:

Given

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similarly B travels with 20 mph and in 2 hours

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Thus distance between A and B is

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2 years ago

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2 years ago

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Ierofanga [76]

Answer:

$T_{m }$ = 4.86 s

$T_{e}$ = 1.98 s

Explanation:

<u><em>Given:</em></u>

Length = l = 1 m

Acceleration due to gravity of moon = $g_{m}$ = 1.67 m/s²

Acceleration due to gravity of Earth = $g_{e}$ = 10 m/s²

<u><em>Required:</em></u>

Time period = T = ?

<u><em>Formula:</em></u>

T = 2π $\sqrt{\frac{l}{g} }$

<u><em>Solution:</em></u>

<u>For moon</u>

<em>Putting the givens,</em>

T = 2(3.14) $\sqrt{\frac{1}{1.67} }$

T = 6.3 $\sqrt{0.6}$

T = 6.3 × 0.77

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<u>For Earth,</u>

<em>Putting the givens</em>

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2 years ago