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goldfiish [28.3K]
3 years ago
5

Consider a civilization broadcasting a signal with a power of 1.2×104 watts. The Arecibo radio telescope, which is about 300 met

ers in diameter, could detect this signal if it is coming from as far away as 110 light-years. Suppose instead that the signal is being broadcast from the other side of the Milky Way Galaxy, about 70000 light-years away.
Physics
1 answer:
Talja [164]3 years ago
6 0
The same power (1.9×10^4 watts) gets diminished by Inverse square law 
<span>(ratio of distances)² </span>
<span>= (138/70000)² </span>
<span>= 3.886506 X 10^-6 . </span>
<span>This is the diminution factor for the given sensitivity of the telescope. But at 3.8865 millionth below the sensitivity its is far below detection; it needs to be enhanced by collecting the energy over an area so many times more (by an aperture multiplied by same factor) </span>
<span>1/[3.886506 X 10^-6] = 257298.88 </span>
<span>In other words the diameter should have the ratio of square root of this </span>
<span>(70000/138). </span>
<span>This multiplied by 300m dish gives </span>
<span>300 X (70000/138) = 152173.913 m = 152.1739 km. </span>
<span>This should be the aperture of the new telescope for detecting the signal.</span>
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Answer:

Time, t = 3.2 ms

Explanation:

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F=ma\\\\F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{0.622\times (3.85-4.23)}{72.9}\\\\t=0.0032\ s\\\\\text{or}\\\\t=3.2\ ms

So, the ball is in contact with the floor for 3.2 ms.

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Explanation:

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Here, the field is directed out of the plane of the paper, this gives the induced current in counterclockwise direction.

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