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Minchanka [31]
3 years ago
7

A hoodlum throws a stone vertically downward with an initial speed v0 from the roof of a building, a height h above the ground.

(a) how long does it take the stone to reach the ground? (b) what is the speed of the stone at impact? give your answers in terms of the given variables and g.
Physics
1 answer:
Vaselesa [24]3 years ago
6 0
V2=u2+2as
v2=144+600
v2=744
v=√744
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Answer:

2.06 m/s

Explanation:

From the law of conservation of linear momentum, the sum of momentum before and after collision are equal. Considering this case where we have frictionless surface, no momentum is lost in the process.

Momentum before collision

Momentum is given by p=mv where m and v represent mass. The initial sum of momentum will be 9v+(27*0.5)=9v+13.5

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