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Minchanka [31]
4 years ago
7

A hoodlum throws a stone vertically downward with an initial speed v0 from the roof of a building, a height h above the ground.

(a) how long does it take the stone to reach the ground? (b) what is the speed of the stone at impact? give your answers in terms of the given variables and g.
Physics
1 answer:
Vaselesa [24]4 years ago
6 0
V2=u2+2as
v2=144+600
v2=744
v=√744
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What is the entropy change of 450 g of water when it changes from liquid to steam at its usual boiling point? For water, <img sr
HACTEHA [7]

Answer:

2726.54 J/K

Explanation:

Entropy change = \frac{m\times L_{v}}{T}

where

m = mass of water = 450g = 0.45kg

L_{v} = 2.26 MJ/kg = 2260000 J/kg

T = temperature at which water change from liquid to steam = 100 degree Celsius = 272 + 100 = 373 degree kelvin.

Entropy change = \frac{0.4\times 2260000}{373} = 2726.54 J/K

3 0
4 years ago
A 65kg teacher (including the parachute) is skydiving! As the parachute opens, the system experiences a 1200N drag.
horrorfan [7]

1) 2 Forces

2) 563 N, upward

3) 8.66 m/s^2, upward

4) Speed is decreasing

Explanation:

1)

There are two forces acting on teacher during his skydiving:

- The force of gravity (also known as weight), acting downward (towards the Earth's centre), of magnitude

W=mg

where

m is the mass of the teacher

g is the acceleration due to gravity

- The air resistance, of magnitude R = 1200 N, acting upward (air resistance always acts in the direction opposite to the direction of motion)

There are no other forces, therefore the correct answer is:

2 Forces

2)

The net force on the system is given by the vector resultant of the two forces described in part 1). Since the two forces act along the same line but in opposite directions, the net force will be equal to the difference between the two forces, so:

F_{net}=W-R=mg-R

where we have chosen downward as positive direction, and where

m = 65 kg is the mass of the teacher

g=9.8 m/s^2 is the acceleration due to gravity

R = 1200 N is the air drag

Therefore, the net force on the teacher is

F_{net}=(65)(9.8)-1200=-563 N

And the negative sign means that the direction of the net force is upward.

3)

The acceleration of the system can be found by using Newton's second law of motion, which can be written as

a=\frac{F_{net}}{m}

where

a is the acceleration

F_{net} is the net force

m is the mass of the teacher

Here we have

F_{net}=-563 N

m = 65 kg

Therefore, the acceleration is

a=\frac{-563}{65}=-8.66 m/s^2

And the negative sign indicates that the direction of the acceleration is opposite to the motion (so, upward).

4)

From part 3), we observed that:

- The motion of the teacher is downward (he is moving downward)

- However, the direction of his acceleration is upward

This means that the velocity and the acceleration of the system have opposite directions.

As we know, the velocity of an accelerating system can be written as

v=u+at

where

v is the velocity after time t

u is the initial velocity

a is the acceleration

Since a is negative, we see that at, so v: this means that the velocity of the teacher is decreasing with time, so, the teacher is slowing down, and therefore his speed is decreasing.

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A girl throws a rock horizontally at 10 m/s from the top of a building, 22 m above street level. Assuming free fall conditions a
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Answer:21.18 m

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22=\frac{1}{2}gt^2

t=\sqrt{\frac{22\times 2}{g}}

t=2.11 s

Horizontal Distance moved

R=u_x\times t

R=10\times 2.11

R=21.18 m

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