All categories

3 years ago

Calculate the average speed (in m/s) of a car that travels 50km in 30 minutes.

Physics

1 answer:

Valentin [98]3 years ago

8 0

100 kmph or 27.7778 m/s

You might be interested in

A mass of 148g stretches a spring 6cm. The mass is set in motion from its equlibrium position with a downward velocity of 10cm/s

zalisa [80]

Answer:

$u(t)=0.78sin12.78t$

Explanation:

We are given that

Mass,m=148 g

Length,L=6 cm

Velocity,u'(0)=10 cm/s

We have to find the position u of the mass at any time t

We know that

$\omega_0=\sqrt{\frac{g}{L}}=\sqrt{\frac{980}{6}}=12.78 rad/s$

Where g= $980 cm/s^2$

$u(t)=Acos12.78 t+Bsin 12.78t$

u(0)=0

Substitute the value

$A=0$

$u'(t)=-12.78Asin12.78t+12.78 Bcos12.78 t$

Substitute u'(0)=10

$12.78B=10$

$B=\frac{10}{12.78}=0.78$

Substitute the values

$u(t)=0.78sin12.78t$

7 0

3 years ago

A force is directly proportional to what ?

pishuonlain [190]

It's mass and acceleration

4 0

3 years ago

Please can i have help with this question

kenny6666 [7]

Opposites attract so north goes to south and Vice versa. When the same poles are facing each other they push away when they are opposites they attract.

8 0

3 years ago

Mercury has one of the lowest specific heats. This fact added to its liquid state at most atmospheric temperatures make it effec

UNO [17]

The specific heat of mercury is 149.4 J/(kgK)

Explanation:

When a substance is supplied with an amount of energy Q, its temperature increases according to the equation:

$\Delta T=\frac{Q}{mC_s}$

where

$\Delta T$ is the increase in temperature

m is the mass of the sample

$C_s$ is its specific heat capacity

For the sample of mercury in this problem we have

Q = 275 J

m = 0.450 kg

$\Delta T = 4.09 K$

Therefore, by re-arranging the equation we find the mercury's specific heat:

$C_s = \frac{Q}{m\Delta T}=\frac{275}{(0.450)(4.09)}=149.4 J/(kgK)$

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

5 0

3 years ago

For a particular reaction, the change in enthalpy is 51kJmole and the activation energy is 109kJmole. Which of the following cou

Ronch [10]

Answer

given,

change in enthalpy = 51 kJ/mole

change in activation energy = 109 kJ/mole

when a reaction is catalysed change in enthalpy between the product and the reactant does not change it remain constant.

where as activation energy of the product and the reactant decreases.

example:

ΔH = 51 kJ/mole

E_a= 83 kJ/mole

here activation energy decrease whereas change in enthalpy remains same.

5 0

3 years ago