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never [62]
3 years ago
10

The ideal temperature at which to study the effect of proteases on protein is 37°C. Why are higher temperatures not advisable?

Physics
2 answers:
elena-14-01-66 [18.8K]3 years ago
7 0

Answer:

The higher temperatures are not advisable because

A) This could contribute to irreversible denaturing of protein.

D) Only at the specified temperature, the protein interacts with the proteases.

Explanation:

The higher temperatures are not advisable because

A) This could contribute to irreversible denaturing of protein.

D) Only at the specified temperature, the protein interacts with the proteases.

1. The protease at a temperature higher than 37 degree is not active

2) The protein you are researching to be destroyed by protease may be denatured and the protease may not function because the protein(s) that it targets are messed up by the structure.

loris [4]3 years ago
3 0

Answer:a

Explanation:

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Sindrei [870]

Answer: True.

Explanation:

A resistance force is also known as friction. And the efficiency of a machine is affected by friction.

A machine of lower efficiency has higher magnitude of friction than a machine of higher efficiency.

Therefore, To obtain the same resistance force, a greater force must be exerted in a machine of lower efficiency than in a machine of higher efficiency. This is true

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3 years ago
A tank of volume 0.25 ft is designed to contain 50 standard cubic feet of air. The temperature is 80° F.Calculate the pressure i
slavikrds [6]

Answer:

The inside Pressure of the tank is 4499.12 lb/ft^{2}

Solution:

As per the question:

Volume of tank, V = 0.25 ft^{3}

The capacity of tank, V' = 50ft^{3}

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Temperature, T = 59^{\circ}F = 288.2 K

Now, from the eqn:

PV = nRT                      (1)

Volume of the gas in the container is constant.

V = V'

Similarly,

P'V' = n'RT'                       (2)

Also,

The amount of gas is double of the first case in the cylinder then:

n' = 2n

\]frac{n'}{n} = 2

where

n and n' are the no. of moles

Now, from eqn (1) and (2):

\frac{PV}{P'V'} = \frac{nRT}{n'RT'}

P' = 2P\frac{T'}{T} = 2\times 2116\times \frac{299.8}{288.2} = 4499.12 lb/ft^{2}

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4 years ago
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Answer:

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A 20kg block is sliding down a 30° ramp at a constant velocity. Calculate the normal force acting on the block. Calculate the co
tatiyna

Let me try:

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Explanation

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dmitriy555 [2]

Answer:

d.) potential for the exchange of genetic material

Explanation:

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3 years ago
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