Drawing on eratosthenes' method, if two observers are due north and south of each other and are separated by 400 km, what is the
1 answer:
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Explanation:
Kepler's third law gives the relationship between the orbital radius and the orbital period of the planet. Its mathematical form is given by :
Here,
G is gravitational constant
M is mass of sun
It means that the mass of Sun is constant for all planets orbiting the sun, assuming circular orbits.
Answer:
t=62 s
Explanation:
Applying the conservation of linear momentum formula:
the initial velocity is zero, we can calculate the man's mass using the gravitational force formula:
now:
That is 0.13m/s due south.
because there is no friction, the man will maintain a constant velocity, so:
The new velocity after 4 s is 40 m/s
The height of the spaceship above the ground after 5 seconds is 1,127.5 m
The given parameters for the first question;
- initial velocity of the car, u = 76 m/s
- acceleration of the car, a = - 9 m/s²
- time of motion, t = 4 s
The new velocity after 4 s is calculated as;
v = u + at
v = 76 + (-9)(4)
v = 76 - 36
v = 40 m/s
(5)
The given parameters;
- height above the ground, h = 500 m
- velocity of spaceship, u = 150 m/s
- time of motion, t = 5
The height of the spaceship above the ground after 5 seconds is calculated as;
Learn more here: brainly.com/question/24527971