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Kipish [7]
3 years ago
9

Which statement explains why the bonds between nonmetals tend to be covalent? The bonds are found to be nondirectional. They hav

e large differences in electronegativity. They have small differences in electronegativity. They have ions that produce an electrostatic pull.
Chemistry
2 answers:
Helga [31]3 years ago
8 0

Answer:

c

Explanation:

Alexandra [31]3 years ago
7 0
Correct Answer: <span>They have small differences in electronegativity (statement 3)
Reason: 
The nature of chemical bond between atoms is primarily driven by the electronegativity  difference between constituent atoms. If electronegativity difference between constituent atoms is significantly higher, ionic bond formation is preferred. On other hand, low difference in electronegativity values, favours formation of covalent bond. 
</span><span>
</span>
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Which property of a substance is not altered by a physical change?
antiseptic1488 [7]
C. Composition

is the answer
3 0
4 years ago
The following models represent three different mixtures of the same solid in water,
velikii [3]

Answer:

A

Explanation:

bcuz the water in it is little

3 0
3 years ago
When Mendeleev started his work on organizing the elements, about how many had
Talja [164]

Answer:

About 60.

Explanation:

Mendeleev knew of 63 elements. He wrote their properties on cards and arranged them in order of atomic mass.

That's how he discovered that the properties of elements are periodic functions of their atomic masses.

8 0
3 years ago
Which statement below matches the correct response with the proper reasoning when comparing the volatility of CH2Cl2 with CH2Br2
Nutka1998 [239]

Answer:

b. CH₂Cl₂ is more volatile than CH₂Br₂ because of the large dispersion forces in CH₂Br₂

Explanation:

CH₂Cl₂ is more volatile than CH₂Br₂ (b.p of CH₂Cl₂ = 39,6 °C; b.p of CH₂Br₂ = 96,95°C). Thus, c. and d. are FALSE

Dipole-dipole interactions in CH₂Cl₂ are greater than the dipole-dipole interactions in CH₂Br₂ because Cl is more electronegative that Br (Cl = 3,16; Br = 2,96). But this mean CH₂Cl₂ is less volatile than CH₂Br₂ but it is false.

There are large dispersion forces in CH₂Br₂ because Br has more electrons and protons than Cl. Large disperson forces mean CH₂Br₂ is less volatile than CH₂Cl₂ and it is true.

I hope it helps!

5 0
3 years ago
The activation energy of an uncatalyzed reaction is 95kJ/mol. The addition of a catalyst lowers the activation energy to 55kJ/mo
notka56 [123]

Answer:

a) at 25°C the rate of reaction increases by a factor of 1,027*10^7

b) at 25°C the rate of reaction increases by a factor of 1,777*10^5

Explanation:

using the Arrhenius equation

k= ko*e^(-Ea/RT)

where

k= reaction rate

ko= collision factor

Ea= activation energy

R= ideal gas constant= 8.314 J/mol*K

T= absolute temperature

for the uncatalysed reaction

k1= ko*e^(-Ea1/RT)

for the catalysed reaction

k2= ko*e^(-Ea2/RT)

dividing both equations

k2/k1= e^(-(Ea2-Ea1)/RT)

a) at 25°C

k2/k1 = e^(-(55kJ/mol-95kJ/mol)/(8.314J/mol*K*298K)* (1000J/kJ ) ) = 1,027*10^7

therefore at 25°C , k2/k1 = 1,027*10^6

b) at 125°C

k2/k1 = e^(-(55kJ/mol-95kJ/mol)/(8.314J/mol*K*298K)* (1000J/kJ ) ) = 1,777*10^5

therefore at 125°C , k2/k1 = 1,777*10^5

Note:

when the catalysts is incorporated, the catalysed reaction and the uncatalysed one run in parallel and therefore the real reaction rate is

k real = k1 + k2 = k2 (1+k1/k2)

since k2>>k1 → 1+k1/k2 ≈ 1 and thus k real ≈ k2

6 0
3 years ago
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