Answer:
Explanation:
1.) What is the net force in the horizontal (x) direction?
Fnet = 8 - 3 = 5 N left
2.) what is the acceleration in the horizontal (x) direction?
a = Fnet/m = 5/2 = 2.5 m/s² left
The force per unit length between the two wires is
The magnitude of the force per unit length exerted between two current-carrying wires is given by
where
is the vacuum permeability
are the currents in the two wires
r is the separation between the two wires
For the wires in this problem, we have
r = 2.00 cm = 0.02 m
Substituting into the equation, we find
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Answer: it’s 3 seconds
Answer:1) the total distance is the sum of the two distances
60 km + 45 km = 105 km
2) The displacement is the net movement, or the difference between the initial position and the final position
Call x the initial position, then the final position is x + [60km - 45km]
And the displacement is x + (60km - 45km) - x =60km -45 km = 15 km