Question

307.0 mL of air is at 0 C. What is the volume (L) at 273 C

Answer 1

Use Charle's Law because we are dealing with volume and temperature.

$\frac{v}{t} =\frac{v}{t}$

v₁= 3017.0 ml

t₂ = 0

v₂= ???

t₂= 273°C

Change all mL's to L because the question says "What is the volume (L)...".

3017.0 mL = 3.017 L

Change the temperature into Kelvins:   Kelvin = Celsius + 273.15

0°C = 273.15 K

273°C = 546.15 K

Now you can plug it in the formula:

$\frac{3.017}{273.15} = \frac{v}{546.15}$

Then, do cross multiplication.

(3.017) (546.15) = (273.15) v₂

1,647.73 = (273.15 K) v₂

                                         Divide 273.15 on both sides

6.0296 L= V₂