Method A is Convection
Method B is Conduction
Explanation:
From the problem, we can infer that method A is convection and method B is conduction.
Conduction, convection and radiation are the three main methods of heat transfer.
- Conduction and convection requires material medium to propagate.
- Radiation occurs in the absence of a material medium.
- Conduction mostly occurs in solid. Here, heat is transferred from one hot end to the cold end of the solid. The vibration of the particles in the hot end causes the transfer of kinetic energy to the cold end until thermal equilibrium is reached.
- In convection, heat is primarily transferred in fluids as a result of density differences. Convection involves the motion of the materials of the medium. Hot air is light and it rises whereas cold air is dense and it sinks.
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Answer:
I think the answer is two
Answer:
588.2 mL
Explanation:
- FeSO₄(aq) + 2KOH(aq) → Fe(OH)₂(s) + K₂SO₄(aq)
First we <u>calculate how many Fe⁺² moles reacted</u>, using the given <em>concentration and volume of FeSO₄ solution</em> (the number of FeSO₄ moles is equal to the number of Fe⁺² moles):
- moles = molarity * volume
- 187 mL * 0.692 M = 129.404 mmol Fe⁺²
Then we convert Fe⁺² moles to KOH moles, using the stoichiometric ratios:
- 129.404 mmol Fe⁺² *
= 258.808 mmol KOH
Finally we<u> calculate the required volume of KOH solution</u>, using <em>the given concentration and the calculated moles</em>:
- volume = moles / molarity
- 258.808 mmol KOH / 0.440 M = 588.2 mL
