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erastovalidia [21]
3 years ago
5

The pyruvic acid from glycolysis can be converted to acetic acid, which can enter the citric acid cycle. Because this process is

a cycle, the atoms entering the cycle must balance the atoms that leave. Consider carbon balance in the citric acid cycle. How many CO 2 molecules leave the cycle for each acetic acid molecule that enters? For this question, assume that carbon only enters as acetic acid and exits as CO 2 . Note that acetic acid has two carbon atoms. You can determine the number of carbon atoms in carbon dioxide from its formula, CO 2 .
Chemistry
1 answer:
netineya [11]3 years ago
5 0

Answer: 2CO2, 8CO2

Explanation:

During glycolysis one molecule of glucose is oxidized to two molecules of pyruvic acid (3 carbon molecule). Pyruvic acid is converted to acetyl CoA(2 carbon molecule) by the pyruvate dehydrogenase complex.

For each acetic acid that enters the citric acid cycle 2 molecules of CO2 is given off.

For one glucose molecule produces 2 acetyl CoA

2 acetyl groups + 6 NAD+ + 2 FAD + 2 ADP + 2 Pi yields 4 CO2 + 6 NADH + 6 H+ + 2 FADH2 + 2 ATP.

Hence 4 molecules of acetic acid is completely oxidized to 8 molecules of CO2.

You might be interested in
Consider the combustion of octane (C8H18)
Masja [62]
First, you have to find now many moles of octane are present in 191.6g of octane.  To do this you need to do this you need to divide 191.6g by its molar mass (which is 114g/mol).  This will give you 1.681 moles of octane.  Then you need to use the fact that 2 moles of octane are us ed to make 16 moles of carbon dioxide to find how many moles of carbon dioxide 1.681mole of octane produces. To do this you need to multiply 1.681mole by 16/2 to get 13.45mol carbon dioxide.  The final step is to find the number of grams presswnt in 13.446 moles of carbon dioxide.  To do this you need to multiply 13.446 mole by carbon dioxides molar mass (which is 44g/mol) to get 591.6 g of carbon dioxide.
Therefore, 591.6g of carbon dioxide is produced when 191.6 grams of octane is burned.

I hope this helps. Let me know in the comments if anything is unclear.
8 0
3 years ago
4. which answer below is the formula mass of a water molecule?
mars1129 [50]
The answer is 18.02 g/mol
6 0
3 years ago
How many atoms of oxygen are in 0.100 mol of silicon dioxide?
lys-0071 [83]
1) Silicon dioxide formula: SiO2  ....... 2 is a subscript for the O atom

2) From the formula you have 1 molecula of SiO2 contains 1 atom of SiO2

3) Then, 0.100 mol of SiO2 contains 0.1 mol of Si

4) Multiply by Avogadro's number: 0.100mol *  6.022*10^23 atoms/mol= 6.02*10^22 atoms

Answer: 6.02*10^22 atoms
3 0
3 years ago
How many moles are in 2.5L of 1.75 M Na2CO3
mixas84 [53]

Answer: There are 4.375 moles in 2.5 L of 1.75 M Na_2CO_3

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}      

Molarity of solution = 1.75 M

Volume of solution = 2.5 L  

Putting values in equation , we get:

1.75M=\frac{\text{Moles of} Na_2CO_3}{2.5L}\\\\\text{Moles of }Na_2CO_3=1.75mol/L\times 2.5L=4.375mol

6 0
3 years ago
How many moles of nitrous oxide gas (N2O) is contained in 20.0 L balloon at a pressure of 1.09 atm and a temperature of 298K? Ro
prohojiy [21]

Answer:

There are 0,89 moles of nitrous oxide gas  in the balloon.

Explanation:

We apply the formula of the ideal gases, we clear n (number of moles); we use the ideal gas constant R = 0.082 l atm / K mol:

PV= nRT ---> n= PV/RT

n= 1,09 atm x 20,0 L /0.082 l atm / K mol x 298 K

<em>n= 0,89212637 mol</em>

7 0
3 years ago
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