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erastovalidia [21]
3 years ago
5

The pyruvic acid from glycolysis can be converted to acetic acid, which can enter the citric acid cycle. Because this process is

a cycle, the atoms entering the cycle must balance the atoms that leave. Consider carbon balance in the citric acid cycle. How many CO 2 molecules leave the cycle for each acetic acid molecule that enters? For this question, assume that carbon only enters as acetic acid and exits as CO 2 . Note that acetic acid has two carbon atoms. You can determine the number of carbon atoms in carbon dioxide from its formula, CO 2 .
Chemistry
1 answer:
netineya [11]3 years ago
5 0

Answer: 2CO2, 8CO2

Explanation:

During glycolysis one molecule of glucose is oxidized to two molecules of pyruvic acid (3 carbon molecule). Pyruvic acid is converted to acetyl CoA(2 carbon molecule) by the pyruvate dehydrogenase complex.

For each acetic acid that enters the citric acid cycle 2 molecules of CO2 is given off.

For one glucose molecule produces 2 acetyl CoA

2 acetyl groups + 6 NAD+ + 2 FAD + 2 ADP + 2 Pi yields 4 CO2 + 6 NADH + 6 H+ + 2 FADH2 + 2 ATP.

Hence 4 molecules of acetic acid is completely oxidized to 8 molecules of CO2.

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If the two atoms participating in a bond have an electron negativity difference of 1.9 , what type of of bond would they be part
brilliants [131]

Answer:

Polar covalent bond.

Explanation:

When the bond is formed between the atoms by sharing the electrons the bond thus have covalent character.   The atom with larger electronegativity attract the electron pair more towards it self and becomes partial negative while the other atom becomes partial positive.  When the electronegativity difference is less than 0.4 the bond is non polar covalent.

When bonded atoms have greater electronegativity difference i.e 2 or greater than two the bond is ionic because electron is transfer from low electronegative atom to highest electronegative atom.

For example:

In water the electronegativity of oxygen is 3.44 and hydrogen is 2.2. That's why electron pair attracted more towards oxygen, thus oxygen becomes partial negative and hydrogen becomes partial positive.

In case of H₂, Cl₂, Br₂ the bond has very high covalent character because of zero electronegativity difference.

7 0
3 years ago
In redox half-reactions, a more positive standard reduction potential means I. the oxidized form has a higher affinity for elect
qwelly [4]

Answer:

The 1st and 4th options are correct

I.the oxidized form has a higher affinity for electrons

IV. the greater the tendency for the oxidized form to accept electrons

Explanation:

Half reaction can be described as the oxidation or reduction reaction in a redox reaction.it is In the redox rection there is a change in the oxidation states of Chemical species involved. the oxidized form in the redox has a higher affinity for electrons and the greater the tendency for the oxidized form to accept electrons.

Standard reduction potential which is also referred to as standard cell potential can be described as the potential difference that exist between cathode and anode of the cell. In the standard reduction potential most times the species will be reduced which is usually analysed in a reduction half reaction.

(Standard Hydrogen Electrode) is utilized when determining the Standard reduction or potentials of a chemical specie. this is because of Hydrogen having zero reduction and oxidation potentials, as a result of this a measured potential of any species is compared with that of Hydrogen, the difference helps to know the potential reduction of that particular specie.

4 0
3 years ago
Nicotine is a toxic substance present in tobacco leaves. There are two lone pairs in the structure of nicotine. In general, loca
Harlamova29_29 [7]

Answer:

B.Lone pair in pyrrolidine ring is localized and, therefore, is expected to be more reactive.

Explanation:

There are two nitrogen atoms bearing lone pairs of electrons in the structure of nicotine as shown in the image attached.

One nitrogen atom is found in the pyrrolidine ring. The lone pair on this nitrogen atom is localized hence it is more reactive than the lone pair of electrons found on the nitrogen atom in the pyridine ring which is delocalized a shown in the image attached to this answer.

8 0
3 years ago
Balance the following equation in acidic conditions Phases are optional. S2O3 2- + Cu 2+ ---> S4O6 2- + Cu+
jonny [76]

To balance the the chemical reaction, the number of moles per element is balance is both side of the reaction and also the charge in both sides of the reation. to balnce the reaction:

S2O3 2- + Cu 2+ ---> S4O6 2- + Cu+

2S2O3 2- + Cu 2+ ---> S4O6 2- + Cu+ + e

3 0
3 years ago
Which one is ittt? help please:)
Alexus [3.1K]

Answer:

b

Explanation:

4 0
3 years ago
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