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Vesnalui [34]
3 years ago
14

Please help me

Physics
2 answers:
Helen [10]3 years ago
7 0

Answer:

15 protons and 18 electrons

General Formulas and Concepts:

<u>Chemistry</u>

  • Reading a Periodic Table
  • Element Number
  • Neutral Atoms
  • Ions

Explanation:

We are given the element P. P is 15 on the Periodic Table, meaning it has 15 protons and 15 electrons (all elements are in neutral form).

P³⁻ ion means the element now has a negative charge of 3. We know protons have a positive charge and electrons have a negative charge. 3- means we will have more electrons than protons.

Therefore, P³⁻ would have 15 protons and <em>18</em> electrons:

15 (+) + 18 (-) = 3 (-)

Digiron [165]3 years ago
3 0
15 protons and 18 electrons
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Determine an appropriate size for a square cross-section solid steel shaft to transmit 260 hp at a speed of 550 rev/min if the m
Phantasy [73]

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Explanation:

Given

Power=260\ hp\approx 260\times 746=193.96\ KW

speed N=550\ rev/min

allowable shear stress (\tau )_{max}=15\ kpsi\approx 103.421\ MPa

Power is given by

P=\frac{2\pi NT}{60}

193.96=\frac{2\pi 550\times T}{60}

T=3367.6\ N-m

From Torsion Formula

\frac{T}{J}=\frac{\tau }{r}-----1

where J=Polar section modulus

T=Torque

\tau=shear stress

For square cross section

r=\frac{a}{2}

where a=side of square

J=\frac{a^4}{6}

Substituting the values in equation 1

\frac{3376.6}{\frac{a^4}{6}}=\frac{103.421\times 10^6}{\frac{a}{2}}

a=0.04605\ m

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7 0
3 years ago
A 6.00-mH solenoid is connected in series with a 5.0-μF capacitor and an AC source. The solenoid has internal resistance 3.0 Ω w
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Answer:

5773.50269 Hz

23 A

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L = Inductance = 6 mH

C = Capacitance = 5 μF

R = Resistance = 3 Ω

\epsilon = Maximum emf = 69 V

Resonant angular frequency is given by

\omega=\dfrac{1}{\sqrt{LC}}\\\Rightarrow \omega=\dfrac{1}{\sqrt{6\times 10^{-3}\times 5\times 10^{-6}}}\\\Rightarrow \omega=5773.50269\ Hz

The resonant angular frequency is 5773.50269 Hz

Current is given by

I=\dfrac{\epsilon}{R}\\\Rightarrow I=\dfrac{69}{3}\\\Rightarrow I=23\ A

The current amplitude at the resonant angular frequency is 23 A

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