Ask question

Ask question

All categories

3 years ago

9

What is the net force on a bright red mercedes convertible traveling along a straight road at a steady speed of 100 hm/h?

1 answer:

Neporo4naja [7]3 years ago

6 0

I don't know what " hm/h " means as a unit of speed. But if the bright red object is traveling in a straight line at a constant speed, then its acceleration is zero, and that means that the net force acting on it is zero. The same would be true of a car of any other color traveling with the same velocity.

You might be interested in

Which lists types of materials from most conductive to least conductive?

Lilit [14]

Superconductor, conductor, semiconductor, insulator

7 0

3 years ago

Read 2 more answers

a worker uses a board that is 7 m long to pry up a bolder A small rock is used for the fulcrum and is placed 2.5 m from the resi

e-lub [12.9K]

Answer:

en español por

favor para entender un poco más

4 0

3 years ago

An airplane flying at an altitude of 6 miles passes directly over a radar antenna. When the airplane is 10 miles away (s = 10),

Novosadov [1.4K]

Answer:

Explanation:

Given

altitude of the Plane $h=6\ miles$

When Airplane is $s=10\ miles$ away

Distance is changing at the rate of $\frac{\mathrm{d} s}{\mathrm{d} t}=290\ mph$

From diagram we can write as

$h^2+x^2=s^2$

differentiate above equation w.r.t time

$2h\frac{\mathrm{d} h}{\mathrm{d} t}+2x\frac{\mathrm{d} x}{\mathrm{d} t}=2s\frac{\mathrm{d} s}{\mathrm{d} t}$

as altitude is not changing therefore $\frac{\mathrm{d} h}{\mathrm{d} t}=0$

$0+x\frac{\mathrm{d} x}{\mathrm{d} t}=s\frac{\mathrm{d} s}{\mathrm{d} t}$

at $s=10\ miles\ and\ h=6\ miles$

substitute the value we get $x=\sqrt{10^2-6^2}=8\ miles$

$8\times \frac{\mathrm{d} x}{\mathrm{d} t}=10\times 290$

$\frac{\mathrm{d} x}{\mathrm{d} t}=362.5\ mph$

5 0

4 years ago

Hey can anyone help me out in dis pls!

patriot [66]

Answer:

D

Explanation:

3 0

4 years ago

Read 2 more answers

How do i do a Wavelength and frequency problem

KengaRu [80]

Answer:

wavelength = v/f or wavelength equals to velocity over frequency

frequency= v/w or velocity over wavelength

frequency= 1/p or one over period or time

7 0

4 years ago