All categories

3 years ago

How hot is the sun? First answer gets brainliest. :)

Physics

2 answers:

Andreyy893 years ago

5 0

Inner (Core) Temperature = 1.5 crore degree celsius
Surface temp. = 6 k degree celsius

Hope this helps!

AleksAgata [21]3 years ago

3 0

<span>5,778 K is how hot the sun is. ( ty will be receiving my brainliest now :) </span>

You might be interested in

A 0.015 kg marble sliding to the right at 22.5 cm/s on a frictionless surface makes an elastic head-on collision with a 0.015 kg

slava [35]

Answer:

Explanation:

mass of first marble $m_1=m=0.015\ kg$

Initial velocity of the first marble $u_1=22.5\ m/s$

considering right side as positive

Mass of second marble

$m_2=m=0.015\ kg\\u_2=-18\ cm/s$

After collision first marble moves to the left with a velocity of 18 cm/s

i.e. $v_1=-18\ cm/s$

considering $v_2$ be the velocity of second marble after collision

The Coefficient of restitution is 1 for an elastic collision

$e=\frac{v_2-v_1}{u_1-u_2}$

Putting values

$1=\frac{v_2-(-18)}{22.5-(-18)}\\22.5+18=v_2+18\\v_2=22.5\ m/s$

So, the velocity of the second marble is 22.5 m/s to the right after the collision

(b)Initial kinetic energy = $0.5\times 0.015\times (22.5\times 10^{-2})^2+0.5\times 0.015\times (18\times 10^{-2})^2=6.22\times 10^{-4}\ J$

Final kinetic energy=

$0.5\times 0.015\times (18\times 10^{-2})^2+0.5\times 0.015\times (22.5\times 10^{-2})^2=6.22\times 10^{-4}\ J$

6 0

3 years ago

What conducts heat the be best?

olga nikolaevna [1]

It just has to be metal

4 0

3 years ago

A perpetual-motion machine can never be built because it is not possible to eliminate...

bazaltina [42]

The answer is: [C]: "elasticity" .
________________________________________

4 0

3 years ago

Read 2 more answers

An antelope moving with constant acceleration of 2m/s2 covers

soldier1979 [14.2K]

Explanation:

we use the formula for that 6s duration ....

<h2> S = ut + 1/2 at² </h2><h3>s = displacement </h3><h3>u = initial velocity </h3><h3>a = acceleration </h3><h3>t = time </h3>

so , S = (5 × 6) + (1/2 × 2 × 6 × 6 )

S = 30 + 36

and we can use this formula to find the final velocity.......

<h2> V = U + at </h2><h3>V = final velocity </h3><h3>a = acceleration </h3><h3>u = initial velocity </h3><h3>t = time </h3>

so , V = 5 + (2×6)

V = 5 + 12

6 0

2 years ago

A box of negligible mass rests at the left end of a 2.00-m, 25.0-kg plank (Fig. P11.43). The width of the box is 75.0 cm, and sa

Sati [7]

Answer:

Required mass of sand is 20 kg

Explanation:

Given:

Mass of the plank = 25 kg

Distance of the Center of gravity of the Plank from the fulcrum = $\frac{2}{2}-0.50 = 0.5m$

Distance of the Center of gravity of the sand box from the fulcrum = $\frac{2}{2}-\frac{0.75}{2}= 0.625m$

Balancing the torque due to the plank and the sand box with respect to the fulcrum

Torque = Force × perpendicular distance

thus, we get

(25 × g) × 0.5 = weight of sand × 0.625

where, g is the acceleration due to gravity

(25 × g) × 0.5 = (mass of sand × g) × 0.625

mass of sand = 20 kg

<u>Hence, the required mass of the sand is </u><u>20 kg</u>

8 0

3 years ago