Answer:
Tarzan will be moving at 7.4 m/s.
Explanation:
From the question given above, the following data were obtained:
Height (h) of cliff = 2.8 m
Initial velocity (u) = 0 m/s
Final velocity (v) =?
NOTE: Acceleration due to gravity (g) = 9.8 m/s²
Finally, we shall determine how fast (i.e final velocity) Tarzan will be moving at the bottom. This can be obtained as follow:
v² = u² + 2gh
v² = 0² + (2 × 9.8 × 2.8)
v² = 0 + 54.88
v² = 54.88
Take the square root of both side
v = √54.88
v = 7.4 m/s
Therefore, Tarzan will be moving at 7.4 m/s at the bottom.
The planet Mercury. Hope this helps
Hmmm...maybe it would be because since you're staying still then things appear to go by quickly.
Answer:
for the fill in the blanks
1- static
2-kinetic
3-coeffiecient
4-opposite to
5-sin theta
6-cos theta
im not sure however what to do with the top part or if its even part of what you need help with
Answer:
Explanation:
The net force exerted on the mass is the sum of tension force and the external force of gravity.
is the tension force.
is the force of gravity.
where 
is the rope's radius from the fixed point.
From the net force equation above:
Hence the tension force is 6.046N
