1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
laiz [17]
3 years ago
10

Why can you see your own reflected image in a mirror but not on a dry, painted wall?

Physics
1 answer:
kaheart [24]3 years ago
7 0
A wall uses diffuse reflection while a mirror uses specular reflection. For example, when parallel light rays enter a mirror, they remain parallel when exiting the mirror, allowing you to see a reflection of the light rays. On the contrary, when incident light rays enter a wall which is painted, the rays scatter, not allowing you to see anything but a painted wall. 
You might be interested in
Acoustic encoding is the encoding of <br> images<br><br> sounds<br><br> meanings<br><br> acronyms
Alex787 [66]
Acoustic encoding in the encoding of sounds, that is, in laymen's terms. But in a more grammatically superior way of speech it is the encoding of auditory impulses.
5 0
3 years ago
Read 2 more answers
Guys can someone help me
tensa zangetsu [6.8K]

your answer will be B . becasue light can be transformed into heat .

4 0
3 years ago
Enlight the contribution of science and technology for current pandemic of Corona virus??​
Tju [1.3M]

The vaccine ofcourse. They helped in making the vaccine.

3 0
3 years ago
A student hangs a wood block from a spring. The student pulls the block downwards so the spring is stretched and holds the block
Murrr4er [49]
Kinetic energy because of the wood plank is just still and not moving it’s potential but since it’s asking which one it doesn’t have it doesn’t have kinetic energy cause it’s not moving
6 0
3 years ago
Desde una altura de 120 m se deja caer un cuerpo. Calcular a los 2,5 s i) la rapidez que lleva; ii) cuánto ha descendido; iii) c
stira [4]

Answer:

i) 24.5 m/s

ii) 30,656 m

iii) 89,344 m

Explanation:

Desde una altura de 120 m se deja caer un cuerpo. Calcule a 2.5 s i) la velocidad que toma; ii) cuánto ha disminuido; iii) cuánto queda por hacer

i) Los parámetros dados son;

Altura inicial, s = 120 m

El tiempo en caída libre = 2.5 s

De la ecuación de caída libre, tenemos;

v = u + gt

Dónde:

u = Velocidad inicial = 0 m / s

g = Aceleración debida a la gravedad = 9.81 m / s²

t = Tiempo de caída libre = 2.5 s

Por lo tanto;

v = 0 + 9.8 × 2.5 = 24.5 m / s

ii) El nivel que el cuerpo ha alcanzado en 2.5 segundos está dado por la relación

s = u · t + 1/2 · g · t²

= 0 × 2.5 + 1/2 × 9.81 × 2.5² = 30.656 m

iii) La altura restante = 120 - 30.656 = 89.344 m.

6 0
3 years ago
Other questions:
  • a canary sits 10 m from the edge of a 30-m-long clothesline, and a grackle sits 5 m from the other end. The rope is pulled by tw
    5·1 answer
  • A radar astronomer who is new at the job claims she beamed radio waves to Jupiter and received an echo exactly 48 min later. Sho
    13·1 answer
  • RACTICE Uranium (molar mass = 283.03 g/mol) has the largest molar mass of any element naturally found on Earth. What is the mass
    15·1 answer
  • You’re driving your car towards an intersection. A Porsche is stopped at the red light. You’re traveling at 36 km/h (10 m/s). As
    7·1 answer
  • A cube and a square pyramid were joined to form the composite solid. A cube with side lengths of 12 inches. A square pyramid wit
    7·2 answers
  • Name on contact force and one field force acting on you right now
    11·1 answer
  • 11. Two point charges, initially 1 cm apart, are moved to a distance of 3 cm apart. By what factor
    13·1 answer
  • What is the acceleration of a 160kg object if a force of 150N is applied to it?
    7·1 answer
  • Please help me <br> the formula is E = P x t
    10·1 answer
  • Which of the following statements is true? Thunderstorms are not dangerous The eye of a hurricane is the most danger Tornadoes f
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!