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PtichkaEL [24]
3 years ago
9

How tilted is the axis of the earth's rotation as compared to the plane of the earth's orbit?

Physics
2 answers:
Phantasy [73]3 years ago
6 0
C. 23.5 degrees
This tilt in the axis causes the seasons. 
Hope this helps.
ryzh [129]3 years ago
6 0
The Earth's axis is about 66.5 degrees out of the plane of the orbit.
It's about 23.5 degrees away from being "straight up and down".
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If you pull up on a bucket with a tension force of 15 N and the bucket has a weight of 15 N, what is the net force acting on the
fredd [130]

Answer:

F = 0 [N]

Explanation:

To solve this problem we must perform a summation of forces in the direction of the vertical axis. Where the positive force is that of the tension of the upward force, while the force exerted by the weight is directed downward with a negative sign.

ΣF = 0

15 - 15 + F = 0

F = 0 [N]

3 0
3 years ago
How to find coefficient of lift from coefficient of pressure?
Alona [7]
It is the number in front of the equation
4 0
3 years ago
a wooden block has a mass of 1.2 kg, a specific heat of 710, and is at a temperature of 25*C. what is the block's final temperat
mash [69]

The final temperature of the block is 27.5^{\circ} C

Explanation:

The amount of thermal energy Q supplied to a substance is related to the increase in temperature of the substance, \Delta T, according to the equation

Q=mC_s \Delta T

where:

m is the mass of the substance

C_s is the specific heat capacity of the substance

In this problem, we have:

m = 1.2 kg is the mass of the block

Q = 2,130 J is the amount of energy supplied to the block

C_s = 710 J/kg^{\circ}C is the specific heat capacity of the block

Solving for \Delta T, we find the increase in temperature:

\Delta T = \frac{Q}{m C_s}=\frac{2130}{(1.2)(710)}=2.5^{\circ}C

And since the initial temperature was

T_i = 25^{\circ}C

The final temperature will be

T_f = T_i + \Delta T = 25+2.5=27.5^{\circ} C

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

8 0
3 years ago
A child jumps from a moving sled with a speed of 2.2 m/s and in the
butalik [34]

The initial velocity of the sled will be 7.34 m/sec. V is the initial velocity of the sled.

<h3>What is the law of conservation of momentum?</h3>

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

(m₁)  mass of child = 38 kg

(u₁) is the initial velocity child = 2.2 m/s

(m₂) is the mass of sled = 68 kg

(u₂) is the initial velocity of sled = ?

(v) is the velocity after collision = 5.5 m/s

According to the law of conservation of momentum;

Momentum before collision =Momentum after collision

\rm  m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\(38 \times  2.2) + (68 \times V) = 5.5 \times (38+68) \\\\ 83.6 + 68V = 5.5 \times 106 \\\\  83.6 + 68V =583 \\\\ \rm 68\ V= 583 -83.6 \\\\ \rm 68 \ V= 499.4\\\\ V= 7.34 \ m/sec

Hence,the initial velocity of the sled will be 7.34 m/sec.

To learn more about the law of conservation of momentum refer;

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4 0
2 years ago
During an in-class demonstration of momentum change and impulse, Mr. H asks Jerome (102 kg) and Michael (98 kg) to sit on a larg
Brums [2.3K]

Answer:

2.6 m/s

Explanation:

mass of Jerome (Mj) = 102 kg

mass of Micheal (Mm) = 98 kg

mass of each cart (Mc) = 14 kg

recoil speed of Jerone and Micheal after push (Vi) = ?

mass of Suzie (Ms) = 44 kg

Suzie's speed after push (Vs) = 9.6 m/s

From the conservation of momentum, initial momentum = final momentum

Since they all are initially at rest the initial momentum is 0 and hence the final momentum is also 0.

Therefore for the final momentum we have

(Mj + Mm + Mc) Vi - (Ms + Mc) Vs = 0  ( the negative sign is because they move in opposite directions)

((102 + 98 + 14) x Vi ) - ((44 + 14) x 9.6) = 0

(214 x Vi) - (58 x 9.6) = 0

214 Vi = 556.8

Vi = 556.8 / 214 = 2.6 m/s

6 0
4 years ago
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