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Delvig [45]
3 years ago
8

Using Ohm’s Law, explain how resistance changes in relation to current, assuming that voltage remains constant.

Physics
1 answer:
Cerrena [4.2K]3 years ago
7 0
V=IR so voltage is directly proportional to current. So for a given resistance increasing the voltage will result in a high current as well. This is because resistance is proportional to the voltage over the current. Ex: I=V/R
Hope this helped. THANKYOU for asking. <span />
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A book is sitting on a desk. What best describes the normal force acting on the book?
Marat540 [252]

Explanation:

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In a particular region, there is a uniform magnetic field with a magnitude of 2.00 T. You take a particle with a charge of +6.00
expeople1 [14]

Answer:

a) 1.68 N b) 0 c) 14.5º

Explanation:

a)

  • The force on a charge moving in a magnetic field, is a vector perpendicular to the plane defined by the velocity of the charge and the magnetic field.
  • The magnitude of the force F is given by the following expression:

       F = q*v*B*sin\theta (1)

  • where q= magnitude of the charge of the particle, v=velocity of the particle, B= magnitude of the magnetic field, and θ= angle between v and B.
  • Replacing by the known values in (1) we have:

       F = q*v*B*sin\theta (1) = 6.00e-6C*1.40e5m/s*2T*sin\theta=\\ \\ F= 1.68N*sin\theta

  • The maximum possible value of F happens when sin θ =1
  • This means that v and B are perpendicular each other (in the same plane)
  • So, Fmax = 1.68 N

b)

  • If the maximum possible value of F happens when sin θ = 1, the minimum possible is when sin θ = 0.
  • In this case, when v  and B are parallel each other, the force is just 0.

c)

  • If the force is 0.25 of the maximum possible, (which is when sin θ =1), this means that sin θ = 0.25, as it can be seen below:

       F_{\theta} = q*v*B*sin \theta = 0.25*Fmax\\ F_{\theta} = q*v*B*sin\theta= 0.25 (q*v*B*sin 90) \\ sin \theta = 0.25

       \theta = sin^{-1} (0.25) =14.5 deg

  • The angle between the velocity v and the magnetic field B is 14.5º.
3 0
4 years ago
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BartSMP [9]

Answer:

The intensity of 4 lawn movers is 86 dB.

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dB = 10 log\left ( \frac{4I}{Io} \right )\\\\dB=10log\left ( \frac{4\times10^{-4}}{10^{-12}} \right )\\\\dB = 86 dB\\

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Answer:

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Explanation:

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