An example of a system with decreasing gravitational potential energy is a ball in free fall.
At its initial height h, the ball has a gravitational potential energy equal to
where m is the ball mass and g is the gravitational acceleration. As the ball falls toward the ground, its height h decreases, and so its gravitational potential energy decreases as well, according to the formula
where h' is the new height of the ball.
Answer:
There are many different systems involved in when we exercise, the three main ones are the Respiratory system which is involved in breathing the circulatory system which is about circulation of blood around the body and finally the muscular system and finally the Muscular system which is about how we move.
Explanation:
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Answer:
a) v = 88.54 m/s
b) vf = 26.4 m/s
Explanation:
Given that;
m = 1400.0 kg
a)
by using the energy conservation
loss in potential energy is equal to gain in kinetic energy
mg × ( 3200-2800) = 1/2 ×m×v²
so
1400 × 9.8 × 400 = 0.5 × 1400 × v²
5488000 = 700v²
v² = 5488000 / 700
v² = 7840
v = √7840
v = 88.54 m/s
b)
Work done by all forces is equal to change in KE
W_gravity + W_non - conservative = 1/2×m×(vf² - vi²)
we substitute
1400 × 9.8 × ( 3200-2800) - (5 × 10⁶) = 1/2 × 1400 × (vf² -0 )
488000 = 700 vf²
vf² = 488000 / 700
vf² = 697.1428
vf = √697.1428
vf = 26.4 m/s
Answer:
The sphere's volume charge density is 2.58 μC/m³.
Explanation:
Given that,
Radius of sphere R= 8.40 cm
Electric field 
Distance r= 16.8 cm
We need to calculate the sphere's volume charge density
Using Gauss's law
Put the value into the formula
Hence, The sphere's volume charge density is 2.58 μC/m³.
