Question

rewrite as equivalent rational expressions with denominator (3x−8)(x−5)(x−3). 4/3x2−23x+40,9x/3x2−17x+24

Answer 1

Answer:

Step-by-step explanation:

\frac{4}{3x²-23x+40}

=\frac{4}{3x²-15x-8x+40}

=\frac{4}{3x(x-5)-8(x-5)}

=\frac{4}{(x-5)(3x-8)}

=\frac{4(x-3)}{(x-5)(3x-8)(x-3)}

2.

\frac{9x}{3x²-17x+24}

=\frac{9x}{3x²-9x-8x+24}

=\frac{9x}{3x(x-3)-8(x-3)}

=\frac{9x}{(x-3)(3x-8)}

=\frac{9x(x-5)}{(3x-8)(x-5)(x-3)}